Construct a section (or slice) through 3D Regions












3












$begingroup$


I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.



gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]


Mathematica graphics



Now I define an InfinitePlane that I would like to slice through my regions.



ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]


Mathematica graphics



How do I get the 2D Region lying in the plane? Is this possible?



This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.



Edit



@kglr suggest I can go further with ClipPanes. Here is his suggestion.



rc = RegionPlot3D[rr, ClipPlanes -> ip, 
ClipPlanesStyle -> Opacity[0.1, Green]]


Mathematica graphics



This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?



Edit 2



Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.



dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]


Mathematica graphics



One can then extract the lines and reduce the coordinates to the values in the plane.



LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]


Mathematica graphics



This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!










share|improve this question











$endgroup$












  • $begingroup$
    maybe RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
    $endgroup$
    – kglr
    6 hours ago










  • $begingroup$
    @kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
    $endgroup$
    – Hugh
    6 hours ago










  • $begingroup$
    dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}] gives lines which can be further processed to form the polygons.
    $endgroup$
    – kglr
    5 hours ago
















3












$begingroup$


I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.



gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]


Mathematica graphics



Now I define an InfinitePlane that I would like to slice through my regions.



ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]


Mathematica graphics



How do I get the 2D Region lying in the plane? Is this possible?



This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.



Edit



@kglr suggest I can go further with ClipPanes. Here is his suggestion.



rc = RegionPlot3D[rr, ClipPlanes -> ip, 
ClipPlanesStyle -> Opacity[0.1, Green]]


Mathematica graphics



This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?



Edit 2



Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.



dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]


Mathematica graphics



One can then extract the lines and reduce the coordinates to the values in the plane.



LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]


Mathematica graphics



This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!










share|improve this question











$endgroup$












  • $begingroup$
    maybe RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
    $endgroup$
    – kglr
    6 hours ago










  • $begingroup$
    @kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
    $endgroup$
    – Hugh
    6 hours ago










  • $begingroup$
    dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}] gives lines which can be further processed to form the polygons.
    $endgroup$
    – kglr
    5 hours ago














3












3








3





$begingroup$


I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.



gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]


Mathematica graphics



Now I define an InfinitePlane that I would like to slice through my regions.



ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]


Mathematica graphics



How do I get the 2D Region lying in the plane? Is this possible?



This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.



Edit



@kglr suggest I can go further with ClipPanes. Here is his suggestion.



rc = RegionPlot3D[rr, ClipPlanes -> ip, 
ClipPlanesStyle -> Opacity[0.1, Green]]


Mathematica graphics



This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?



Edit 2



Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.



dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]


Mathematica graphics



One can then extract the lines and reduce the coordinates to the values in the plane.



LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]


Mathematica graphics



This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!










share|improve this question











$endgroup$




I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.



gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]


Mathematica graphics



Now I define an InfinitePlane that I would like to slice through my regions.



ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]


Mathematica graphics



How do I get the 2D Region lying in the plane? Is this possible?



This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.



Edit



@kglr suggest I can go further with ClipPanes. Here is his suggestion.



rc = RegionPlot3D[rr, ClipPlanes -> ip, 
ClipPlanesStyle -> Opacity[0.1, Green]]


Mathematica graphics



This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?



Edit 2



Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.



dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]


Mathematica graphics



One can then extract the lines and reduce the coordinates to the values in the plane.



LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]


Mathematica graphics



This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!







regions






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 5 hours ago







Hugh

















asked 6 hours ago









HughHugh

6,39521945




6,39521945












  • $begingroup$
    maybe RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
    $endgroup$
    – kglr
    6 hours ago










  • $begingroup$
    @kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
    $endgroup$
    – Hugh
    6 hours ago










  • $begingroup$
    dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}] gives lines which can be further processed to form the polygons.
    $endgroup$
    – kglr
    5 hours ago


















  • $begingroup$
    maybe RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
    $endgroup$
    – kglr
    6 hours ago










  • $begingroup$
    @kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
    $endgroup$
    – Hugh
    6 hours ago










  • $begingroup$
    dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}] gives lines which can be further processed to form the polygons.
    $endgroup$
    – kglr
    5 hours ago
















$begingroup$
maybe RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
$endgroup$
– kglr
6 hours ago




$begingroup$
maybe RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
$endgroup$
– kglr
6 hours ago












$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
6 hours ago




$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
6 hours ago












$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}] gives lines which can be further processed to form the polygons.
$endgroup$
– kglr
5 hours ago




$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}] gives lines which can be further processed to form the polygons.
$endgroup$
– kglr
5 hours ago










1 Answer
1






active

oldest

votes


















4












$begingroup$

Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.



Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:



cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here



We can easily project to 2d as well:



BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]


enter image description here





We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.



halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;

halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr

halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];

halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];

clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;

InverseTransformedRegion[clip, rt]
]

halfSpaceClip[___] = $Failed;


The same example:



cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here



A non axes aligned plane:



cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here






share|improve this answer











$endgroup$













  • $begingroup$
    Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
    $endgroup$
    – Hugh
    5 hours ago










  • $begingroup$
    @Hugh Yes that is one way. See my latest edit.
    $endgroup$
    – Chip Hurst
    5 hours ago










  • $begingroup$
    Excellent many thanks.
    $endgroup$
    – Hugh
    4 hours ago











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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4












$begingroup$

Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.



Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:



cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here



We can easily project to 2d as well:



BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]


enter image description here





We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.



halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;

halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr

halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];

halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];

clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;

InverseTransformedRegion[clip, rt]
]

halfSpaceClip[___] = $Failed;


The same example:



cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here



A non axes aligned plane:



cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here






share|improve this answer











$endgroup$













  • $begingroup$
    Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
    $endgroup$
    – Hugh
    5 hours ago










  • $begingroup$
    @Hugh Yes that is one way. See my latest edit.
    $endgroup$
    – Chip Hurst
    5 hours ago










  • $begingroup$
    Excellent many thanks.
    $endgroup$
    – Hugh
    4 hours ago
















4












$begingroup$

Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.



Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:



cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here



We can easily project to 2d as well:



BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]


enter image description here





We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.



halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;

halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr

halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];

halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];

clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;

InverseTransformedRegion[clip, rt]
]

halfSpaceClip[___] = $Failed;


The same example:



cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here



A non axes aligned plane:



cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here






share|improve this answer











$endgroup$













  • $begingroup$
    Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
    $endgroup$
    – Hugh
    5 hours ago










  • $begingroup$
    @Hugh Yes that is one way. See my latest edit.
    $endgroup$
    – Chip Hurst
    5 hours ago










  • $begingroup$
    Excellent many thanks.
    $endgroup$
    – Hugh
    4 hours ago














4












4








4





$begingroup$

Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.



Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:



cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here



We can easily project to 2d as well:



BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]


enter image description here





We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.



halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;

halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr

halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];

halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];

clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;

InverseTransformedRegion[clip, rt]
]

halfSpaceClip[___] = $Failed;


The same example:



cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here



A non axes aligned plane:



cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here






share|improve this answer











$endgroup$



Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.



Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:



cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here



We can easily project to 2d as well:



BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]


enter image description here





We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.



halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;

halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr

halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];

halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];

clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;

InverseTransformedRegion[clip, rt]
]

halfSpaceClip[___] = $Failed;


The same example:



cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here



A non axes aligned plane:



cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];

holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];

slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];

Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 4 hours ago

























answered 5 hours ago









Chip HurstChip Hurst

21.8k15790




21.8k15790












  • $begingroup$
    Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
    $endgroup$
    – Hugh
    5 hours ago










  • $begingroup$
    @Hugh Yes that is one way. See my latest edit.
    $endgroup$
    – Chip Hurst
    5 hours ago










  • $begingroup$
    Excellent many thanks.
    $endgroup$
    – Hugh
    4 hours ago


















  • $begingroup$
    Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
    $endgroup$
    – Hugh
    5 hours ago










  • $begingroup$
    @Hugh Yes that is one way. See my latest edit.
    $endgroup$
    – Chip Hurst
    5 hours ago










  • $begingroup$
    Excellent many thanks.
    $endgroup$
    – Hugh
    4 hours ago
















$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
5 hours ago




$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
5 hours ago












$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
5 hours ago




$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
5 hours ago












$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
4 hours ago




$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
4 hours ago


















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