Conservation of Mass and Energy












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I was thinking about some physics (relativity in particular), when it suddenly occurred to me that all my life I had been balancing chemical equations assuming conservation of mass, but I was disregarding energy!



For example, consider combustion:
$$CH_4 + 2O_2 >>> 2H_2O + CO_2 + {Energy}$$



However, since energy was released, some mass should have been converted to energy right? Why is the equation reflecting a balance in mass?










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    1












    $begingroup$


    I was thinking about some physics (relativity in particular), when it suddenly occurred to me that all my life I had been balancing chemical equations assuming conservation of mass, but I was disregarding energy!



    For example, consider combustion:
    $$CH_4 + 2O_2 >>> 2H_2O + CO_2 + {Energy}$$



    However, since energy was released, some mass should have been converted to energy right? Why is the equation reflecting a balance in mass?










    share|cite|improve this question











    $endgroup$















      1












      1








      1





      $begingroup$


      I was thinking about some physics (relativity in particular), when it suddenly occurred to me that all my life I had been balancing chemical equations assuming conservation of mass, but I was disregarding energy!



      For example, consider combustion:
      $$CH_4 + 2O_2 >>> 2H_2O + CO_2 + {Energy}$$



      However, since energy was released, some mass should have been converted to energy right? Why is the equation reflecting a balance in mass?










      share|cite|improve this question











      $endgroup$




      I was thinking about some physics (relativity in particular), when it suddenly occurred to me that all my life I had been balancing chemical equations assuming conservation of mass, but I was disregarding energy!



      For example, consider combustion:
      $$CH_4 + 2O_2 >>> 2H_2O + CO_2 + {Energy}$$



      However, since energy was released, some mass should have been converted to energy right? Why is the equation reflecting a balance in mass?







      special-relativity conservation-laws mass-energy physical-chemistry






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      share|cite|improve this question













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      share|cite|improve this question








      edited 56 mins ago









      Aaron Stevens

      12.8k42248




      12.8k42248










      asked 1 hour ago









      Dude156Dude156

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          3 Answers
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          2












          $begingroup$

          Adding to TechDroid's answer, energy is also present in chemical bonds. When some higher energy (less stable) bonds are broken to form lower energy (more stable) ones (i.e. exothermic reactions), that energy difference can be released as energy.



          So, almost all of that "+ energy" is due to the energy being released from the bonds themselves, and not the matter.






          share|cite|improve this answer











          $endgroup$





















            1












            $begingroup$

            It actually does, but the amount converted is so small it's considered insignificant in the real world context. Based on the Einstein's famous equation ($E=mc^2$), a lot of energy can be extracted from a really small mass, and the reaction of methane and oxygen produces relatively small amount of energy which equates to a lot more smaller merely insignificant mass. The atomic bomb testiments to the amount of energy just some few kilograms of mass can decay into.




            In addition the notion of the energy gained to achieve freedom for each atom reacting has to be given up to form a stable bond (that which sounds logical but I'm not entirely certain since I've not explored that domain very much) is also a solid argument to consider.







            share|cite|improve this answer











            $endgroup$













            • $begingroup$
              scientificamerican.com/article/…
              $endgroup$
              – safesphere
              49 mins ago










            • $begingroup$
              Well, Einstein has taken it all. But thanks for the link, it added something.
              $endgroup$
              – TechDroid
              11 mins ago



















            0












            $begingroup$

            All the energy released is in the form of potential energy (of the electrons) falling to a lower (in general closer average positions) to the positive nuclei. This is similar to an apple falling off a tree. When this happens photons are released (no mass), molecules/atoms speed up and vibrations within the molecules and atoms increase (kinetic energy). All your chemical equations will have an energy balance but in addition you will need to take into account hidden thermodynamics, such as increased pressure and expansion of gases for example. This stuff is first year university, you will also learn about entropy ( why does salt melt ice?) which is another thermodynamic related energy concept required to balance.



            In these reactions NO mass is converted to energy, mass is always conserved. In a nuclear reaction you again get photons, increased atomic/molecular motion but in addition you get high velocity sub-atomic particles like neutrons. Most (like >99% if I recall from wiki) of the mass is again conserved! You just get new types of atoms formed and isotopes (atoms that have absorbed a neutron). A few photons are indeed a result of a complex nuclear reaction where E=mc2 applies. But these are not of the same nature of the photons produced in a chemical reaction.






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              3 Answers
              3






              active

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              3 Answers
              3






              active

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              active

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              active

              oldest

              votes









              2












              $begingroup$

              Adding to TechDroid's answer, energy is also present in chemical bonds. When some higher energy (less stable) bonds are broken to form lower energy (more stable) ones (i.e. exothermic reactions), that energy difference can be released as energy.



              So, almost all of that "+ energy" is due to the energy being released from the bonds themselves, and not the matter.






              share|cite|improve this answer











              $endgroup$


















                2












                $begingroup$

                Adding to TechDroid's answer, energy is also present in chemical bonds. When some higher energy (less stable) bonds are broken to form lower energy (more stable) ones (i.e. exothermic reactions), that energy difference can be released as energy.



                So, almost all of that "+ energy" is due to the energy being released from the bonds themselves, and not the matter.






                share|cite|improve this answer











                $endgroup$
















                  2












                  2








                  2





                  $begingroup$

                  Adding to TechDroid's answer, energy is also present in chemical bonds. When some higher energy (less stable) bonds are broken to form lower energy (more stable) ones (i.e. exothermic reactions), that energy difference can be released as energy.



                  So, almost all of that "+ energy" is due to the energy being released from the bonds themselves, and not the matter.






                  share|cite|improve this answer











                  $endgroup$



                  Adding to TechDroid's answer, energy is also present in chemical bonds. When some higher energy (less stable) bonds are broken to form lower energy (more stable) ones (i.e. exothermic reactions), that energy difference can be released as energy.



                  So, almost all of that "+ energy" is due to the energy being released from the bonds themselves, and not the matter.







                  share|cite|improve this answer














                  share|cite|improve this answer



                  share|cite|improve this answer








                  edited 48 mins ago

























                  answered 57 mins ago









                  F16FalconF16Falcon

                  3007




                  3007























                      1












                      $begingroup$

                      It actually does, but the amount converted is so small it's considered insignificant in the real world context. Based on the Einstein's famous equation ($E=mc^2$), a lot of energy can be extracted from a really small mass, and the reaction of methane and oxygen produces relatively small amount of energy which equates to a lot more smaller merely insignificant mass. The atomic bomb testiments to the amount of energy just some few kilograms of mass can decay into.




                      In addition the notion of the energy gained to achieve freedom for each atom reacting has to be given up to form a stable bond (that which sounds logical but I'm not entirely certain since I've not explored that domain very much) is also a solid argument to consider.







                      share|cite|improve this answer











                      $endgroup$













                      • $begingroup$
                        scientificamerican.com/article/…
                        $endgroup$
                        – safesphere
                        49 mins ago










                      • $begingroup$
                        Well, Einstein has taken it all. But thanks for the link, it added something.
                        $endgroup$
                        – TechDroid
                        11 mins ago
















                      1












                      $begingroup$

                      It actually does, but the amount converted is so small it's considered insignificant in the real world context. Based on the Einstein's famous equation ($E=mc^2$), a lot of energy can be extracted from a really small mass, and the reaction of methane and oxygen produces relatively small amount of energy which equates to a lot more smaller merely insignificant mass. The atomic bomb testiments to the amount of energy just some few kilograms of mass can decay into.




                      In addition the notion of the energy gained to achieve freedom for each atom reacting has to be given up to form a stable bond (that which sounds logical but I'm not entirely certain since I've not explored that domain very much) is also a solid argument to consider.







                      share|cite|improve this answer











                      $endgroup$













                      • $begingroup$
                        scientificamerican.com/article/…
                        $endgroup$
                        – safesphere
                        49 mins ago










                      • $begingroup$
                        Well, Einstein has taken it all. But thanks for the link, it added something.
                        $endgroup$
                        – TechDroid
                        11 mins ago














                      1












                      1








                      1





                      $begingroup$

                      It actually does, but the amount converted is so small it's considered insignificant in the real world context. Based on the Einstein's famous equation ($E=mc^2$), a lot of energy can be extracted from a really small mass, and the reaction of methane and oxygen produces relatively small amount of energy which equates to a lot more smaller merely insignificant mass. The atomic bomb testiments to the amount of energy just some few kilograms of mass can decay into.




                      In addition the notion of the energy gained to achieve freedom for each atom reacting has to be given up to form a stable bond (that which sounds logical but I'm not entirely certain since I've not explored that domain very much) is also a solid argument to consider.







                      share|cite|improve this answer











                      $endgroup$



                      It actually does, but the amount converted is so small it's considered insignificant in the real world context. Based on the Einstein's famous equation ($E=mc^2$), a lot of energy can be extracted from a really small mass, and the reaction of methane and oxygen produces relatively small amount of energy which equates to a lot more smaller merely insignificant mass. The atomic bomb testiments to the amount of energy just some few kilograms of mass can decay into.




                      In addition the notion of the energy gained to achieve freedom for each atom reacting has to be given up to form a stable bond (that which sounds logical but I'm not entirely certain since I've not explored that domain very much) is also a solid argument to consider.








                      share|cite|improve this answer














                      share|cite|improve this answer



                      share|cite|improve this answer








                      edited 13 mins ago

























                      answered 1 hour ago









                      TechDroidTechDroid

                      60912




                      60912












                      • $begingroup$
                        scientificamerican.com/article/…
                        $endgroup$
                        – safesphere
                        49 mins ago










                      • $begingroup$
                        Well, Einstein has taken it all. But thanks for the link, it added something.
                        $endgroup$
                        – TechDroid
                        11 mins ago


















                      • $begingroup$
                        scientificamerican.com/article/…
                        $endgroup$
                        – safesphere
                        49 mins ago










                      • $begingroup$
                        Well, Einstein has taken it all. But thanks for the link, it added something.
                        $endgroup$
                        – TechDroid
                        11 mins ago
















                      $begingroup$
                      scientificamerican.com/article/…
                      $endgroup$
                      – safesphere
                      49 mins ago




                      $begingroup$
                      scientificamerican.com/article/…
                      $endgroup$
                      – safesphere
                      49 mins ago












                      $begingroup$
                      Well, Einstein has taken it all. But thanks for the link, it added something.
                      $endgroup$
                      – TechDroid
                      11 mins ago




                      $begingroup$
                      Well, Einstein has taken it all. But thanks for the link, it added something.
                      $endgroup$
                      – TechDroid
                      11 mins ago











                      0












                      $begingroup$

                      All the energy released is in the form of potential energy (of the electrons) falling to a lower (in general closer average positions) to the positive nuclei. This is similar to an apple falling off a tree. When this happens photons are released (no mass), molecules/atoms speed up and vibrations within the molecules and atoms increase (kinetic energy). All your chemical equations will have an energy balance but in addition you will need to take into account hidden thermodynamics, such as increased pressure and expansion of gases for example. This stuff is first year university, you will also learn about entropy ( why does salt melt ice?) which is another thermodynamic related energy concept required to balance.



                      In these reactions NO mass is converted to energy, mass is always conserved. In a nuclear reaction you again get photons, increased atomic/molecular motion but in addition you get high velocity sub-atomic particles like neutrons. Most (like >99% if I recall from wiki) of the mass is again conserved! You just get new types of atoms formed and isotopes (atoms that have absorbed a neutron). A few photons are indeed a result of a complex nuclear reaction where E=mc2 applies. But these are not of the same nature of the photons produced in a chemical reaction.






                      share|cite|improve this answer









                      $endgroup$


















                        0












                        $begingroup$

                        All the energy released is in the form of potential energy (of the electrons) falling to a lower (in general closer average positions) to the positive nuclei. This is similar to an apple falling off a tree. When this happens photons are released (no mass), molecules/atoms speed up and vibrations within the molecules and atoms increase (kinetic energy). All your chemical equations will have an energy balance but in addition you will need to take into account hidden thermodynamics, such as increased pressure and expansion of gases for example. This stuff is first year university, you will also learn about entropy ( why does salt melt ice?) which is another thermodynamic related energy concept required to balance.



                        In these reactions NO mass is converted to energy, mass is always conserved. In a nuclear reaction you again get photons, increased atomic/molecular motion but in addition you get high velocity sub-atomic particles like neutrons. Most (like >99% if I recall from wiki) of the mass is again conserved! You just get new types of atoms formed and isotopes (atoms that have absorbed a neutron). A few photons are indeed a result of a complex nuclear reaction where E=mc2 applies. But these are not of the same nature of the photons produced in a chemical reaction.






                        share|cite|improve this answer









                        $endgroup$
















                          0












                          0








                          0





                          $begingroup$

                          All the energy released is in the form of potential energy (of the electrons) falling to a lower (in general closer average positions) to the positive nuclei. This is similar to an apple falling off a tree. When this happens photons are released (no mass), molecules/atoms speed up and vibrations within the molecules and atoms increase (kinetic energy). All your chemical equations will have an energy balance but in addition you will need to take into account hidden thermodynamics, such as increased pressure and expansion of gases for example. This stuff is first year university, you will also learn about entropy ( why does salt melt ice?) which is another thermodynamic related energy concept required to balance.



                          In these reactions NO mass is converted to energy, mass is always conserved. In a nuclear reaction you again get photons, increased atomic/molecular motion but in addition you get high velocity sub-atomic particles like neutrons. Most (like >99% if I recall from wiki) of the mass is again conserved! You just get new types of atoms formed and isotopes (atoms that have absorbed a neutron). A few photons are indeed a result of a complex nuclear reaction where E=mc2 applies. But these are not of the same nature of the photons produced in a chemical reaction.






                          share|cite|improve this answer









                          $endgroup$



                          All the energy released is in the form of potential energy (of the electrons) falling to a lower (in general closer average positions) to the positive nuclei. This is similar to an apple falling off a tree. When this happens photons are released (no mass), molecules/atoms speed up and vibrations within the molecules and atoms increase (kinetic energy). All your chemical equations will have an energy balance but in addition you will need to take into account hidden thermodynamics, such as increased pressure and expansion of gases for example. This stuff is first year university, you will also learn about entropy ( why does salt melt ice?) which is another thermodynamic related energy concept required to balance.



                          In these reactions NO mass is converted to energy, mass is always conserved. In a nuclear reaction you again get photons, increased atomic/molecular motion but in addition you get high velocity sub-atomic particles like neutrons. Most (like >99% if I recall from wiki) of the mass is again conserved! You just get new types of atoms formed and isotopes (atoms that have absorbed a neutron). A few photons are indeed a result of a complex nuclear reaction where E=mc2 applies. But these are not of the same nature of the photons produced in a chemical reaction.







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered 18 mins ago









                          PhysicsDavePhysicsDave

                          94547




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