How to interpert ResNet50 Layer Types
$begingroup$
I am trying to recreate the ResNet50 from scratch, but I don't quite understand how to interpret the matrices for the layers.
For instance:
[[1x1,64]
[3x3, 64]
[1x1, 4]] x 3
I know it's supposed to be a convolution layer but what do each of the numbers represent?
deep-learning keras
$endgroup$
add a comment |
$begingroup$
I am trying to recreate the ResNet50 from scratch, but I don't quite understand how to interpret the matrices for the layers.
For instance:
[[1x1,64]
[3x3, 64]
[1x1, 4]] x 3
I know it's supposed to be a convolution layer but what do each of the numbers represent?
deep-learning keras
$endgroup$
add a comment |
$begingroup$
I am trying to recreate the ResNet50 from scratch, but I don't quite understand how to interpret the matrices for the layers.
For instance:
[[1x1,64]
[3x3, 64]
[1x1, 4]] x 3
I know it's supposed to be a convolution layer but what do each of the numbers represent?
deep-learning keras
$endgroup$
I am trying to recreate the ResNet50 from scratch, but I don't quite understand how to interpret the matrices for the layers.
For instance:
[[1x1,64]
[3x3, 64]
[1x1, 4]] x 3
I know it's supposed to be a convolution layer but what do each of the numbers represent?
deep-learning keras
deep-learning keras
asked Jun 12 '18 at 12:19
Rediculously SoutragesRediculously Soutrages
162
162
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
In order to make the explanation clear I will use the example of 34-layers:
First you have a convolutional layer with 64 filters and kernel size of 7x7 (conv1 in your table) followed by a max pooling layer. Note that the stride is specified to be stride = 2 in both cases.
Next, in conv2_x you have the mentioned pooling layer and the following convolution layers. Here the layers are normally grouped in pairs (trios in bigger architectures) because is how the residuals are connected (the arrows jumping each two layers). The first matrix:
begin{equation}begin{bmatrix}
3x3, & 64 \
3x3, & 64
end{bmatrix}*3end{equation}
means that you have 2 layers of kernel_size = 3x3, num_filters = 64 and these are repeated x3. These correspond to the layers between pool,/2 and the filter 128 ones, 6 layers in total (one pair times 3).
Following, we have conv3_x:
begin{equation}begin{bmatrix}
3x3, & 128 \
3x3, & 128
end{bmatrix}*4end{equation}
2 layers of kernel_size = 3x3, num_filters = 128 and these are also repeated but on this occasion times 4. These are the following 8 green layers in the figure.
This continues until the avg_pooling and the softmax.
Be aware that the stride is always 1 except when the filter size increases. This is discusssed in the paper:
Plain Network: Our plain baselines are
mainly inspired by the philosophy of VGG nets. The convolutional layers mostly have 3×3 filters and
follow two simple design rules: (i) for the same output
feature map size, the layers have the same number of filters;
and (ii) if the feature map size is halved, the number
of filters is doubled so as to preserve the time complexity
per layer. We perform downsampling directly by
convolutional layers that have a stride of 2.
Residual Networks: The baseline architectures
are the same as the above plain nets, expect that a shortcut
connection is added to each pair of 3×3 filters.
That is why, each time the number of filters is doubled you will see that the first layer of a different colour specifies num_filters/2.
$endgroup$
$begingroup$
Can you elaborate as to why ResNet-34 and ResNet-50 both define their architecture using the same number of convolutional blocks for each layer? They both define them as [3, 4, 6, 3]. Why is this and how does the architecture differ?
$endgroup$
– Joey Carson
Jan 1 at 21:26
add a comment |
$begingroup$
Your example doesn't refer to a convolutional layer, but a stack of convolutional layers that create a residual block.
Per Table 1 in the original paper, here is an example residual block with some notation:
$[{text{N x N, C}_1atoptext{M x M, C}_2}] text{ x L} $
- $text{N x N}$ and $text{M x M}$ specify the size of the kernel used in that layer. In the paper the authors call them filters.
- $text{C}_1$ and $text{C}_2$ refer to the number of channels in that convolutional layer.
- $text{L}$ is the number of times this block is repeated for that residual layer.
Good luck, hope this helps!
$endgroup$
$begingroup$
Is there a specific way I'm supposed to make this using something like Keras? Or is it just as simple as: cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,))
$endgroup$
– Rediculously Soutrages
Jun 13 '18 at 19:56
$begingroup$
That table glosses a lot of implementation detail. For example, and as TitoOrt mentions below, the first layer of each new block requires a stride of 2 to halve the feature map from the previous block. Additionally, you have to add the input of the residual block to its output, which is the piece that makes this a residual network and not just a convolutional neural network. If you're intent on trying to do it from scratch, all I can say is read the paper very closely. If you're new to Keras to boot, I'd suggest looking at some of tutorials on building neural nets in Keras.
$endgroup$
– tm1212
Jun 13 '18 at 20:20
$begingroup$
Have a look at how resnet* are defined in Kerala docs itself, they use different block funds and then seive them together!
$endgroup$
– Aditya
Sep 11 '18 at 1:48
add a comment |
$begingroup$
I hope this notebook will help you to understand better. The implementation is in Keras so it's quick grasp!
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
In order to make the explanation clear I will use the example of 34-layers:
First you have a convolutional layer with 64 filters and kernel size of 7x7 (conv1 in your table) followed by a max pooling layer. Note that the stride is specified to be stride = 2 in both cases.
Next, in conv2_x you have the mentioned pooling layer and the following convolution layers. Here the layers are normally grouped in pairs (trios in bigger architectures) because is how the residuals are connected (the arrows jumping each two layers). The first matrix:
begin{equation}begin{bmatrix}
3x3, & 64 \
3x3, & 64
end{bmatrix}*3end{equation}
means that you have 2 layers of kernel_size = 3x3, num_filters = 64 and these are repeated x3. These correspond to the layers between pool,/2 and the filter 128 ones, 6 layers in total (one pair times 3).
Following, we have conv3_x:
begin{equation}begin{bmatrix}
3x3, & 128 \
3x3, & 128
end{bmatrix}*4end{equation}
2 layers of kernel_size = 3x3, num_filters = 128 and these are also repeated but on this occasion times 4. These are the following 8 green layers in the figure.
This continues until the avg_pooling and the softmax.
Be aware that the stride is always 1 except when the filter size increases. This is discusssed in the paper:
Plain Network: Our plain baselines are
mainly inspired by the philosophy of VGG nets. The convolutional layers mostly have 3×3 filters and
follow two simple design rules: (i) for the same output
feature map size, the layers have the same number of filters;
and (ii) if the feature map size is halved, the number
of filters is doubled so as to preserve the time complexity
per layer. We perform downsampling directly by
convolutional layers that have a stride of 2.
Residual Networks: The baseline architectures
are the same as the above plain nets, expect that a shortcut
connection is added to each pair of 3×3 filters.
That is why, each time the number of filters is doubled you will see that the first layer of a different colour specifies num_filters/2.
$endgroup$
$begingroup$
Can you elaborate as to why ResNet-34 and ResNet-50 both define their architecture using the same number of convolutional blocks for each layer? They both define them as [3, 4, 6, 3]. Why is this and how does the architecture differ?
$endgroup$
– Joey Carson
Jan 1 at 21:26
add a comment |
$begingroup$
In order to make the explanation clear I will use the example of 34-layers:
First you have a convolutional layer with 64 filters and kernel size of 7x7 (conv1 in your table) followed by a max pooling layer. Note that the stride is specified to be stride = 2 in both cases.
Next, in conv2_x you have the mentioned pooling layer and the following convolution layers. Here the layers are normally grouped in pairs (trios in bigger architectures) because is how the residuals are connected (the arrows jumping each two layers). The first matrix:
begin{equation}begin{bmatrix}
3x3, & 64 \
3x3, & 64
end{bmatrix}*3end{equation}
means that you have 2 layers of kernel_size = 3x3, num_filters = 64 and these are repeated x3. These correspond to the layers between pool,/2 and the filter 128 ones, 6 layers in total (one pair times 3).
Following, we have conv3_x:
begin{equation}begin{bmatrix}
3x3, & 128 \
3x3, & 128
end{bmatrix}*4end{equation}
2 layers of kernel_size = 3x3, num_filters = 128 and these are also repeated but on this occasion times 4. These are the following 8 green layers in the figure.
This continues until the avg_pooling and the softmax.
Be aware that the stride is always 1 except when the filter size increases. This is discusssed in the paper:
Plain Network: Our plain baselines are
mainly inspired by the philosophy of VGG nets. The convolutional layers mostly have 3×3 filters and
follow two simple design rules: (i) for the same output
feature map size, the layers have the same number of filters;
and (ii) if the feature map size is halved, the number
of filters is doubled so as to preserve the time complexity
per layer. We perform downsampling directly by
convolutional layers that have a stride of 2.
Residual Networks: The baseline architectures
are the same as the above plain nets, expect that a shortcut
connection is added to each pair of 3×3 filters.
That is why, each time the number of filters is doubled you will see that the first layer of a different colour specifies num_filters/2.
$endgroup$
$begingroup$
Can you elaborate as to why ResNet-34 and ResNet-50 both define their architecture using the same number of convolutional blocks for each layer? They both define them as [3, 4, 6, 3]. Why is this and how does the architecture differ?
$endgroup$
– Joey Carson
Jan 1 at 21:26
add a comment |
$begingroup$
In order to make the explanation clear I will use the example of 34-layers:
First you have a convolutional layer with 64 filters and kernel size of 7x7 (conv1 in your table) followed by a max pooling layer. Note that the stride is specified to be stride = 2 in both cases.
Next, in conv2_x you have the mentioned pooling layer and the following convolution layers. Here the layers are normally grouped in pairs (trios in bigger architectures) because is how the residuals are connected (the arrows jumping each two layers). The first matrix:
begin{equation}begin{bmatrix}
3x3, & 64 \
3x3, & 64
end{bmatrix}*3end{equation}
means that you have 2 layers of kernel_size = 3x3, num_filters = 64 and these are repeated x3. These correspond to the layers between pool,/2 and the filter 128 ones, 6 layers in total (one pair times 3).
Following, we have conv3_x:
begin{equation}begin{bmatrix}
3x3, & 128 \
3x3, & 128
end{bmatrix}*4end{equation}
2 layers of kernel_size = 3x3, num_filters = 128 and these are also repeated but on this occasion times 4. These are the following 8 green layers in the figure.
This continues until the avg_pooling and the softmax.
Be aware that the stride is always 1 except when the filter size increases. This is discusssed in the paper:
Plain Network: Our plain baselines are
mainly inspired by the philosophy of VGG nets. The convolutional layers mostly have 3×3 filters and
follow two simple design rules: (i) for the same output
feature map size, the layers have the same number of filters;
and (ii) if the feature map size is halved, the number
of filters is doubled so as to preserve the time complexity
per layer. We perform downsampling directly by
convolutional layers that have a stride of 2.
Residual Networks: The baseline architectures
are the same as the above plain nets, expect that a shortcut
connection is added to each pair of 3×3 filters.
That is why, each time the number of filters is doubled you will see that the first layer of a different colour specifies num_filters/2.
$endgroup$
In order to make the explanation clear I will use the example of 34-layers:
First you have a convolutional layer with 64 filters and kernel size of 7x7 (conv1 in your table) followed by a max pooling layer. Note that the stride is specified to be stride = 2 in both cases.
Next, in conv2_x you have the mentioned pooling layer and the following convolution layers. Here the layers are normally grouped in pairs (trios in bigger architectures) because is how the residuals are connected (the arrows jumping each two layers). The first matrix:
begin{equation}begin{bmatrix}
3x3, & 64 \
3x3, & 64
end{bmatrix}*3end{equation}
means that you have 2 layers of kernel_size = 3x3, num_filters = 64 and these are repeated x3. These correspond to the layers between pool,/2 and the filter 128 ones, 6 layers in total (one pair times 3).
Following, we have conv3_x:
begin{equation}begin{bmatrix}
3x3, & 128 \
3x3, & 128
end{bmatrix}*4end{equation}
2 layers of kernel_size = 3x3, num_filters = 128 and these are also repeated but on this occasion times 4. These are the following 8 green layers in the figure.
This continues until the avg_pooling and the softmax.
Be aware that the stride is always 1 except when the filter size increases. This is discusssed in the paper:
Plain Network: Our plain baselines are
mainly inspired by the philosophy of VGG nets. The convolutional layers mostly have 3×3 filters and
follow two simple design rules: (i) for the same output
feature map size, the layers have the same number of filters;
and (ii) if the feature map size is halved, the number
of filters is doubled so as to preserve the time complexity
per layer. We perform downsampling directly by
convolutional layers that have a stride of 2.
Residual Networks: The baseline architectures
are the same as the above plain nets, expect that a shortcut
connection is added to each pair of 3×3 filters.
That is why, each time the number of filters is doubled you will see that the first layer of a different colour specifies num_filters/2.
answered Jun 12 '18 at 13:45
TitoOrtTitoOrt
762215
762215
$begingroup$
Can you elaborate as to why ResNet-34 and ResNet-50 both define their architecture using the same number of convolutional blocks for each layer? They both define them as [3, 4, 6, 3]. Why is this and how does the architecture differ?
$endgroup$
– Joey Carson
Jan 1 at 21:26
add a comment |
$begingroup$
Can you elaborate as to why ResNet-34 and ResNet-50 both define their architecture using the same number of convolutional blocks for each layer? They both define them as [3, 4, 6, 3]. Why is this and how does the architecture differ?
$endgroup$
– Joey Carson
Jan 1 at 21:26
$begingroup$
Can you elaborate as to why ResNet-34 and ResNet-50 both define their architecture using the same number of convolutional blocks for each layer? They both define them as [3, 4, 6, 3]. Why is this and how does the architecture differ?
$endgroup$
– Joey Carson
Jan 1 at 21:26
$begingroup$
Can you elaborate as to why ResNet-34 and ResNet-50 both define their architecture using the same number of convolutional blocks for each layer? They both define them as [3, 4, 6, 3]. Why is this and how does the architecture differ?
$endgroup$
– Joey Carson
Jan 1 at 21:26
add a comment |
$begingroup$
Your example doesn't refer to a convolutional layer, but a stack of convolutional layers that create a residual block.
Per Table 1 in the original paper, here is an example residual block with some notation:
$[{text{N x N, C}_1atoptext{M x M, C}_2}] text{ x L} $
- $text{N x N}$ and $text{M x M}$ specify the size of the kernel used in that layer. In the paper the authors call them filters.
- $text{C}_1$ and $text{C}_2$ refer to the number of channels in that convolutional layer.
- $text{L}$ is the number of times this block is repeated for that residual layer.
Good luck, hope this helps!
$endgroup$
$begingroup$
Is there a specific way I'm supposed to make this using something like Keras? Or is it just as simple as: cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,))
$endgroup$
– Rediculously Soutrages
Jun 13 '18 at 19:56
$begingroup$
That table glosses a lot of implementation detail. For example, and as TitoOrt mentions below, the first layer of each new block requires a stride of 2 to halve the feature map from the previous block. Additionally, you have to add the input of the residual block to its output, which is the piece that makes this a residual network and not just a convolutional neural network. If you're intent on trying to do it from scratch, all I can say is read the paper very closely. If you're new to Keras to boot, I'd suggest looking at some of tutorials on building neural nets in Keras.
$endgroup$
– tm1212
Jun 13 '18 at 20:20
$begingroup$
Have a look at how resnet* are defined in Kerala docs itself, they use different block funds and then seive them together!
$endgroup$
– Aditya
Sep 11 '18 at 1:48
add a comment |
$begingroup$
Your example doesn't refer to a convolutional layer, but a stack of convolutional layers that create a residual block.
Per Table 1 in the original paper, here is an example residual block with some notation:
$[{text{N x N, C}_1atoptext{M x M, C}_2}] text{ x L} $
- $text{N x N}$ and $text{M x M}$ specify the size of the kernel used in that layer. In the paper the authors call them filters.
- $text{C}_1$ and $text{C}_2$ refer to the number of channels in that convolutional layer.
- $text{L}$ is the number of times this block is repeated for that residual layer.
Good luck, hope this helps!
$endgroup$
$begingroup$
Is there a specific way I'm supposed to make this using something like Keras? Or is it just as simple as: cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,))
$endgroup$
– Rediculously Soutrages
Jun 13 '18 at 19:56
$begingroup$
That table glosses a lot of implementation detail. For example, and as TitoOrt mentions below, the first layer of each new block requires a stride of 2 to halve the feature map from the previous block. Additionally, you have to add the input of the residual block to its output, which is the piece that makes this a residual network and not just a convolutional neural network. If you're intent on trying to do it from scratch, all I can say is read the paper very closely. If you're new to Keras to boot, I'd suggest looking at some of tutorials on building neural nets in Keras.
$endgroup$
– tm1212
Jun 13 '18 at 20:20
$begingroup$
Have a look at how resnet* are defined in Kerala docs itself, they use different block funds and then seive them together!
$endgroup$
– Aditya
Sep 11 '18 at 1:48
add a comment |
$begingroup$
Your example doesn't refer to a convolutional layer, but a stack of convolutional layers that create a residual block.
Per Table 1 in the original paper, here is an example residual block with some notation:
$[{text{N x N, C}_1atoptext{M x M, C}_2}] text{ x L} $
- $text{N x N}$ and $text{M x M}$ specify the size of the kernel used in that layer. In the paper the authors call them filters.
- $text{C}_1$ and $text{C}_2$ refer to the number of channels in that convolutional layer.
- $text{L}$ is the number of times this block is repeated for that residual layer.
Good luck, hope this helps!
$endgroup$
Your example doesn't refer to a convolutional layer, but a stack of convolutional layers that create a residual block.
Per Table 1 in the original paper, here is an example residual block with some notation:
$[{text{N x N, C}_1atoptext{M x M, C}_2}] text{ x L} $
- $text{N x N}$ and $text{M x M}$ specify the size of the kernel used in that layer. In the paper the authors call them filters.
- $text{C}_1$ and $text{C}_2$ refer to the number of channels in that convolutional layer.
- $text{L}$ is the number of times this block is repeated for that residual layer.
Good luck, hope this helps!
answered Jun 12 '18 at 13:45
tm1212tm1212
4657
4657
$begingroup$
Is there a specific way I'm supposed to make this using something like Keras? Or is it just as simple as: cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,))
$endgroup$
– Rediculously Soutrages
Jun 13 '18 at 19:56
$begingroup$
That table glosses a lot of implementation detail. For example, and as TitoOrt mentions below, the first layer of each new block requires a stride of 2 to halve the feature map from the previous block. Additionally, you have to add the input of the residual block to its output, which is the piece that makes this a residual network and not just a convolutional neural network. If you're intent on trying to do it from scratch, all I can say is read the paper very closely. If you're new to Keras to boot, I'd suggest looking at some of tutorials on building neural nets in Keras.
$endgroup$
– tm1212
Jun 13 '18 at 20:20
$begingroup$
Have a look at how resnet* are defined in Kerala docs itself, they use different block funds and then seive them together!
$endgroup$
– Aditya
Sep 11 '18 at 1:48
add a comment |
$begingroup$
Is there a specific way I'm supposed to make this using something like Keras? Or is it just as simple as: cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,))
$endgroup$
– Rediculously Soutrages
Jun 13 '18 at 19:56
$begingroup$
That table glosses a lot of implementation detail. For example, and as TitoOrt mentions below, the first layer of each new block requires a stride of 2 to halve the feature map from the previous block. Additionally, you have to add the input of the residual block to its output, which is the piece that makes this a residual network and not just a convolutional neural network. If you're intent on trying to do it from scratch, all I can say is read the paper very closely. If you're new to Keras to boot, I'd suggest looking at some of tutorials on building neural nets in Keras.
$endgroup$
– tm1212
Jun 13 '18 at 20:20
$begingroup$
Have a look at how resnet* are defined in Kerala docs itself, they use different block funds and then seive them together!
$endgroup$
– Aditya
Sep 11 '18 at 1:48
$begingroup$
Is there a specific way I'm supposed to make this using something like Keras? Or is it just as simple as: cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,))
$endgroup$
– Rediculously Soutrages
Jun 13 '18 at 19:56
$begingroup$
Is there a specific way I'm supposed to make this using something like Keras? Or is it just as simple as: cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,)) cnnModel.add(Conv2D( kernel_size= (3,3), input_shape=(256,256,3), filters = 64,))
$endgroup$
– Rediculously Soutrages
Jun 13 '18 at 19:56
$begingroup$
That table glosses a lot of implementation detail. For example, and as TitoOrt mentions below, the first layer of each new block requires a stride of 2 to halve the feature map from the previous block. Additionally, you have to add the input of the residual block to its output, which is the piece that makes this a residual network and not just a convolutional neural network. If you're intent on trying to do it from scratch, all I can say is read the paper very closely. If you're new to Keras to boot, I'd suggest looking at some of tutorials on building neural nets in Keras.
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– tm1212
Jun 13 '18 at 20:20
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That table glosses a lot of implementation detail. For example, and as TitoOrt mentions below, the first layer of each new block requires a stride of 2 to halve the feature map from the previous block. Additionally, you have to add the input of the residual block to its output, which is the piece that makes this a residual network and not just a convolutional neural network. If you're intent on trying to do it from scratch, all I can say is read the paper very closely. If you're new to Keras to boot, I'd suggest looking at some of tutorials on building neural nets in Keras.
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– tm1212
Jun 13 '18 at 20:20
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Have a look at how resnet* are defined in Kerala docs itself, they use different block funds and then seive them together!
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– Aditya
Sep 11 '18 at 1:48
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Have a look at how resnet* are defined in Kerala docs itself, they use different block funds and then seive them together!
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– Aditya
Sep 11 '18 at 1:48
add a comment |
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I hope this notebook will help you to understand better. The implementation is in Keras so it's quick grasp!
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add a comment |
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I hope this notebook will help you to understand better. The implementation is in Keras so it's quick grasp!
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add a comment |
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I hope this notebook will help you to understand better. The implementation is in Keras so it's quick grasp!
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I hope this notebook will help you to understand better. The implementation is in Keras so it's quick grasp!
answered 23 mins ago
anuanu
1686
1686
add a comment |
add a comment |
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