Plotting a Maclaurin series
$begingroup$
Can anyone plot the degree-8 Maclaurin polynomial for the function $(x+1)/((x^2)-9)$ and function $(x+1)/((x^2)-9)$ on the same plot.
Please help, I've tried everything I could think of.
plotting series-expansion
edited 2 hours ago
m_goldberg
89k873200
asked 3 hours ago
niknik
61
New contributor
nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Can anyone plot the degree-8 Maclaurin polynomial for the function $(x+1)/((x^2)-9)$ and function $(x+1)/((x^2)-9)$ on the same plot.
Please help, I've tried everything I could think of.
plotting series-expansion
edited 2 hours ago
m_goldberg
89k873200
asked 3 hours ago
niknik
61
New contributor
nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Possible duplicates: (7559), (130464), (158080), (160684)
$endgroup$
– Michael E2
1 hour ago
add a comment |
$begingroup$
Can anyone plot the degree-8 Maclaurin polynomial for the function $(x+1)/((x^2)-9)$ and function $(x+1)/((x^2)-9)$ on the same plot.
Please help, I've tried everything I could think of.
plotting series-expansion
edited 2 hours ago
m_goldberg
89k873200
asked 3 hours ago
niknik
61
New contributor
nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Can anyone plot the degree-8 Maclaurin polynomial for the function $(x+1)/((x^2)-9)$ and function $(x+1)/((x^2)-9)$ on the same plot.
Please help, I've tried everything I could think of.
plotting series-expansion
plotting series-expansion
edited 2 hours ago
m_goldberg
89k873200
asked 3 hours ago
niknik
61
New contributor
nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 hours ago
m_goldberg
89k873200
asked 3 hours ago
niknik
61
New contributor
nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 hours ago
m_goldberg
89k873200
edited 2 hours ago
m_goldberg
89k873200
edited 2 hours ago
m_goldberg
89k873200
89k873200
asked 3 hours ago
niknik
61
New contributor
nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
niknik
61
asked 3 hours ago
niknik
61
61
New contributor
nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
Possible duplicates: (7559), (130464), (158080), (160684)
$endgroup$
– Michael E2
1 hour ago
add a comment |
1
$begingroup$
Possible duplicates: (7559), (130464), (158080), (160684)
$endgroup$
– Michael E2
1 hour ago
1
1
$begingroup$
Possible duplicates: (7559), (130464), (158080), (160684)
$endgroup$
– Michael E2
1 hour ago
$begingroup$
Possible duplicates: (7559), (130464), (158080), (160684)
$endgroup$
– Michael E2
1 hour ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
The problem is probably that Series returns a SeriesData object. It must be converted to a polynomial with Normal before it can be plotted.
f = (x + 1)/((x^2) - 9);
p = Normal[Series[f, {x, 0, 8}]]
Plot[{f, p}, {x, -2, 2}]
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
60.7k585171
$endgroup$
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
nik is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f195724%2fplotting-a-maclaurin-series%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The problem is probably that Series returns a SeriesData object. It must be converted to a polynomial with Normal before it can be plotted.
f = (x + 1)/((x^2) - 9);
p = Normal[Series[f, {x, 0, 8}]]
Plot[{f, p}, {x, -2, 2}]
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
60.7k585171
$endgroup$
add a comment |
$begingroup$
The problem is probably that Series returns a SeriesData object. It must be converted to a polynomial with Normal before it can be plotted.
f = (x + 1)/((x^2) - 9);
p = Normal[Series[f, {x, 0, 8}]]
Plot[{f, p}, {x, -2, 2}]
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
60.7k585171
$endgroup$
add a comment |
$begingroup$
The problem is probably that Series returns a SeriesData object. It must be converted to a polynomial with Normal before it can be plotted.
f = (x + 1)/((x^2) - 9);
p = Normal[Series[f, {x, 0, 8}]]
Plot[{f, p}, {x, -2, 2}]
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
60.7k585171
$endgroup$
The problem is probably that Series returns a SeriesData object. It must be converted to a polynomial with Normal before it can be plotted.
f = (x + 1)/((x^2) - 9);
p = Normal[Series[f, {x, 0, 8}]]
Plot[{f, p}, {x, -2, 2}]
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
60.7k585171
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
60.7k585171
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
60.7k585171
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
60.7k585171
60.7k585171
add a comment |
add a comment |
nik is a new contributor. Be nice, and check out our Code of Conduct.
nik is a new contributor. Be nice, and check out our Code of Conduct.
nik is a new contributor. Be nice, and check out our Code of Conduct.
nik is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f195724%2fplotting-a-maclaurin-series%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
Possible duplicates: (7559), (130464), (158080), (160684)
$endgroup$
– Michael E2
1 hour ago