how do I measure voltage greater than 5V with arduino?












3












$begingroup$


I want to measure varying voltage with arduino and real time data plotting has to be done.
But the supply voltage will be 10V and the arduino is not supposed to have more than 5V.
Is there anyway I can solve this problem?
Do you have any recommendation for circuit design?





schematic





simulate this circuit – Schematic created using CircuitLab






arduino circuit-design high-voltage voltage-measurement







share|improve this question









New contributor




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$endgroup$












  • $begingroup$
    use one of the ideas presented in the answers below to measure the voltage between the ground and the collector of Q1
    $endgroup$
    – jsotola
    4 mins ago
















3












$begingroup$


I want to measure varying voltage with arduino and real time data plotting has to be done.
But the supply voltage will be 10V and the arduino is not supposed to have more than 5V.
Is there anyway I can solve this problem?
Do you have any recommendation for circuit design?





schematic





simulate this circuit – Schematic created using CircuitLab






arduino circuit-design high-voltage voltage-measurement







share|improve this question









New contributor




Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    use one of the ideas presented in the answers below to measure the voltage between the ground and the collector of Q1
    $endgroup$
    – jsotola
    4 mins ago














3












3








3





$begingroup$


I want to measure varying voltage with arduino and real time data plotting has to be done.
But the supply voltage will be 10V and the arduino is not supposed to have more than 5V.
Is there anyway I can solve this problem?
Do you have any recommendation for circuit design?





schematic





simulate this circuit – Schematic created using CircuitLab






arduino circuit-design high-voltage voltage-measurement







share|improve this question









New contributor




Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I want to measure varying voltage with arduino and real time data plotting has to be done.
But the supply voltage will be 10V and the arduino is not supposed to have more than 5V.
Is there anyway I can solve this problem?
Do you have any recommendation for circuit design?





schematic





simulate this circuit – Schematic created using CircuitLab






arduino circuit-design high-voltage voltage-measurement




arduino circuit-design high-voltage voltage-measurement






share|improve this question









New contributor




Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 3 hours ago







Michael













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asked 3 hours ago









MichaelMichael

163




163




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  • $begingroup$
    use one of the ideas presented in the answers below to measure the voltage between the ground and the collector of Q1
    $endgroup$
    – jsotola
    4 mins ago


















  • $begingroup$
    use one of the ideas presented in the answers below to measure the voltage between the ground and the collector of Q1
    $endgroup$
    – jsotola
    4 mins ago
















$begingroup$
use one of the ideas presented in the answers below to measure the voltage between the ground and the collector of Q1
$endgroup$
– jsotola
4 mins ago




$begingroup$
use one of the ideas presented in the answers below to measure the voltage between the ground and the collector of Q1
$endgroup$
– jsotola
4 mins ago










2 Answers
2






active

oldest

votes


















3












$begingroup$

You can make a voltage divider (see e.g. Wikipedia: Voltage Divider





Make sure R1 and R2 are equal, so instead of 10 V max, you get half (5V max).



Connect Vout to an analog pin from the Arduino and use analogRead to read the voltage (0-5V).



You have to make sure the resistors can handle the current.






share|improve this answer











$endgroup$





















    2












    $begingroup$

    Step down the voltage with a resistive divider and buffer it with an rail-to-rail input and output op-amp wired up as a voltage follower. This buffers the resistance in the resistive divider from the ADC so the divider resistance does not skew your ADC reading. This, in turn, lets you use high resistances in the divider so that the divider itself doesn't load down and skew your signal source. You always want a low output impedance going into a high input impedance so that the signal source is driven strongly and doesn't get loaded down which skews and distorts it.



    In your case you have a signal source driving a resistive divider, then you have a resistive divider the ADC. THerefore, you want the resistive divider to be very high relative to your signal source's output impedance, but you also want it to be very low relative to your ADC's input impedance. Without the buffer, you have to compromise between the two. The buffer works by having a ridiculously high input impedance that the divider plugs into and has a very low output impedance that drives the ADC.



    Higher resistances also reduces power consumption and heat. Using higher resistances without a buffer will also slow down the rate at which your ADC can sample and still have the reading make sense since it slows down the charging of the ADC sampling capacitor. You don't always need a buffer, but it's often a good idea.



    If you do not use an op-amp with rail-to-rail input and output, then you will have to divide the voltage down more than is necessary and will not be able to make full use of your ADC's input range.



    The op-amp can be a 5V one since the resistive divider, if sized properly to step down 10V, will never allow anything above 5V to enter the op-amp unless the 10V source itself becomes higher than 10V.



    enter image description here






    share|improve this answer










    New contributor




    Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$













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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3












      $begingroup$

      You can make a voltage divider (see e.g. Wikipedia: Voltage Divider





      Make sure R1 and R2 are equal, so instead of 10 V max, you get half (5V max).



      Connect Vout to an analog pin from the Arduino and use analogRead to read the voltage (0-5V).



      You have to make sure the resistors can handle the current.






      share|improve this answer











      $endgroup$


















        3












        $begingroup$

        You can make a voltage divider (see e.g. Wikipedia: Voltage Divider





        Make sure R1 and R2 are equal, so instead of 10 V max, you get half (5V max).



        Connect Vout to an analog pin from the Arduino and use analogRead to read the voltage (0-5V).



        You have to make sure the resistors can handle the current.






        share|improve this answer











        $endgroup$
















          3












          3








          3





          $begingroup$

          You can make a voltage divider (see e.g. Wikipedia: Voltage Divider





          Make sure R1 and R2 are equal, so instead of 10 V max, you get half (5V max).



          Connect Vout to an analog pin from the Arduino and use analogRead to read the voltage (0-5V).



          You have to make sure the resistors can handle the current.






          share|improve this answer











          $endgroup$



          You can make a voltage divider (see e.g. Wikipedia: Voltage Divider





          Make sure R1 and R2 are equal, so instead of 10 V max, you get half (5V max).



          Connect Vout to an analog pin from the Arduino and use analogRead to read the voltage (0-5V).



          You have to make sure the resistors can handle the current.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 3 hours ago

























          answered 3 hours ago









          Michel KeijzersMichel Keijzers

          6,14092864




          6,14092864

























              2












              $begingroup$

              Step down the voltage with a resistive divider and buffer it with an rail-to-rail input and output op-amp wired up as a voltage follower. This buffers the resistance in the resistive divider from the ADC so the divider resistance does not skew your ADC reading. This, in turn, lets you use high resistances in the divider so that the divider itself doesn't load down and skew your signal source. You always want a low output impedance going into a high input impedance so that the signal source is driven strongly and doesn't get loaded down which skews and distorts it.



              In your case you have a signal source driving a resistive divider, then you have a resistive divider the ADC. THerefore, you want the resistive divider to be very high relative to your signal source's output impedance, but you also want it to be very low relative to your ADC's input impedance. Without the buffer, you have to compromise between the two. The buffer works by having a ridiculously high input impedance that the divider plugs into and has a very low output impedance that drives the ADC.



              Higher resistances also reduces power consumption and heat. Using higher resistances without a buffer will also slow down the rate at which your ADC can sample and still have the reading make sense since it slows down the charging of the ADC sampling capacitor. You don't always need a buffer, but it's often a good idea.



              If you do not use an op-amp with rail-to-rail input and output, then you will have to divide the voltage down more than is necessary and will not be able to make full use of your ADC's input range.



              The op-amp can be a 5V one since the resistive divider, if sized properly to step down 10V, will never allow anything above 5V to enter the op-amp unless the 10V source itself becomes higher than 10V.



              enter image description here






              share|improve this answer










              New contributor




              Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.






              $endgroup$


















                2












                $begingroup$

                Step down the voltage with a resistive divider and buffer it with an rail-to-rail input and output op-amp wired up as a voltage follower. This buffers the resistance in the resistive divider from the ADC so the divider resistance does not skew your ADC reading. This, in turn, lets you use high resistances in the divider so that the divider itself doesn't load down and skew your signal source. You always want a low output impedance going into a high input impedance so that the signal source is driven strongly and doesn't get loaded down which skews and distorts it.



                In your case you have a signal source driving a resistive divider, then you have a resistive divider the ADC. THerefore, you want the resistive divider to be very high relative to your signal source's output impedance, but you also want it to be very low relative to your ADC's input impedance. Without the buffer, you have to compromise between the two. The buffer works by having a ridiculously high input impedance that the divider plugs into and has a very low output impedance that drives the ADC.



                Higher resistances also reduces power consumption and heat. Using higher resistances without a buffer will also slow down the rate at which your ADC can sample and still have the reading make sense since it slows down the charging of the ADC sampling capacitor. You don't always need a buffer, but it's often a good idea.



                If you do not use an op-amp with rail-to-rail input and output, then you will have to divide the voltage down more than is necessary and will not be able to make full use of your ADC's input range.



                The op-amp can be a 5V one since the resistive divider, if sized properly to step down 10V, will never allow anything above 5V to enter the op-amp unless the 10V source itself becomes higher than 10V.



                enter image description here






                share|improve this answer










                New contributor




                Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                $endgroup$
















                  2












                  2








                  2





                  $begingroup$

                  Step down the voltage with a resistive divider and buffer it with an rail-to-rail input and output op-amp wired up as a voltage follower. This buffers the resistance in the resistive divider from the ADC so the divider resistance does not skew your ADC reading. This, in turn, lets you use high resistances in the divider so that the divider itself doesn't load down and skew your signal source. You always want a low output impedance going into a high input impedance so that the signal source is driven strongly and doesn't get loaded down which skews and distorts it.



                  In your case you have a signal source driving a resistive divider, then you have a resistive divider the ADC. THerefore, you want the resistive divider to be very high relative to your signal source's output impedance, but you also want it to be very low relative to your ADC's input impedance. Without the buffer, you have to compromise between the two. The buffer works by having a ridiculously high input impedance that the divider plugs into and has a very low output impedance that drives the ADC.



                  Higher resistances also reduces power consumption and heat. Using higher resistances without a buffer will also slow down the rate at which your ADC can sample and still have the reading make sense since it slows down the charging of the ADC sampling capacitor. You don't always need a buffer, but it's often a good idea.



                  If you do not use an op-amp with rail-to-rail input and output, then you will have to divide the voltage down more than is necessary and will not be able to make full use of your ADC's input range.



                  The op-amp can be a 5V one since the resistive divider, if sized properly to step down 10V, will never allow anything above 5V to enter the op-amp unless the 10V source itself becomes higher than 10V.



                  enter image description here






                  share|improve this answer










                  New contributor




                  Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






                  $endgroup$



                  Step down the voltage with a resistive divider and buffer it with an rail-to-rail input and output op-amp wired up as a voltage follower. This buffers the resistance in the resistive divider from the ADC so the divider resistance does not skew your ADC reading. This, in turn, lets you use high resistances in the divider so that the divider itself doesn't load down and skew your signal source. You always want a low output impedance going into a high input impedance so that the signal source is driven strongly and doesn't get loaded down which skews and distorts it.



                  In your case you have a signal source driving a resistive divider, then you have a resistive divider the ADC. THerefore, you want the resistive divider to be very high relative to your signal source's output impedance, but you also want it to be very low relative to your ADC's input impedance. Without the buffer, you have to compromise between the two. The buffer works by having a ridiculously high input impedance that the divider plugs into and has a very low output impedance that drives the ADC.



                  Higher resistances also reduces power consumption and heat. Using higher resistances without a buffer will also slow down the rate at which your ADC can sample and still have the reading make sense since it slows down the charging of the ADC sampling capacitor. You don't always need a buffer, but it's often a good idea.



                  If you do not use an op-amp with rail-to-rail input and output, then you will have to divide the voltage down more than is necessary and will not be able to make full use of your ADC's input range.



                  The op-amp can be a 5V one since the resistive divider, if sized properly to step down 10V, will never allow anything above 5V to enter the op-amp unless the 10V source itself becomes higher than 10V.



                  enter image description here







                  share|improve this answer










                  New contributor




                  Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  share|improve this answer



                  share|improve this answer








                  edited 55 mins ago





















                  New contributor




                  Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  answered 3 hours ago









                  ToorToor

                  212




                  212




                  New contributor




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                  New contributor





                  Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






                  Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






















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