Linear regression incorrect prediction using Matlab
$begingroup$
In the plot below the red crossed line is the actual curve and the crossed blue line is the predicted curve. I am using least squares for linear prediction. I have used 1:79 examples in training and the remaining for testing. The test data points are never seen during training. What is my mistake? Why am I getting such a weird prediction? I want to see the sine curve as the predicted output which should be very close to the original data.
%generate some data
x=linspace(0,2*pi,100)';
y=sin(x); %response
X=x;
y=y;
% Convert matrix values to double
X = double(X(1:79));
y = double(y(1:79));
% Plot data
plot(X, y, 'rx', 'MarkerSize', 10);
m = length(y);
% Add ones column
X = [ones(m, 1) X];
% Gradient Descent with Normal Equation
theta = (pinv(X'*X))*X'*y
% Predict from 80 till last sample
test_samples = x(80:end);
test_samples_val = [ones(length(test_samples),1) test_samples];
% Calculate predicted value
pred_value = test_samples_val * theta;
X = vertcat(X, test_samples_val);
regressionline = X*theta;
% Plot predicted value with blue cross
plot(test_samples, pred_value, 'bx', 'MarkerSize', 10);
linear-regression prediction matlab matrix
$endgroup$
add a comment |
$begingroup$
In the plot below the red crossed line is the actual curve and the crossed blue line is the predicted curve. I am using least squares for linear prediction. I have used 1:79 examples in training and the remaining for testing. The test data points are never seen during training. What is my mistake? Why am I getting such a weird prediction? I want to see the sine curve as the predicted output which should be very close to the original data.
%generate some data
x=linspace(0,2*pi,100)';
y=sin(x); %response
X=x;
y=y;
% Convert matrix values to double
X = double(X(1:79));
y = double(y(1:79));
% Plot data
plot(X, y, 'rx', 'MarkerSize', 10);
m = length(y);
% Add ones column
X = [ones(m, 1) X];
% Gradient Descent with Normal Equation
theta = (pinv(X'*X))*X'*y
% Predict from 80 till last sample
test_samples = x(80:end);
test_samples_val = [ones(length(test_samples),1) test_samples];
% Calculate predicted value
pred_value = test_samples_val * theta;
X = vertcat(X, test_samples_val);
regressionline = X*theta;
% Plot predicted value with blue cross
plot(test_samples, pred_value, 'bx', 'MarkerSize', 10);
linear-regression prediction matlab matrix
$endgroup$
add a comment |
$begingroup$
In the plot below the red crossed line is the actual curve and the crossed blue line is the predicted curve. I am using least squares for linear prediction. I have used 1:79 examples in training and the remaining for testing. The test data points are never seen during training. What is my mistake? Why am I getting such a weird prediction? I want to see the sine curve as the predicted output which should be very close to the original data.
%generate some data
x=linspace(0,2*pi,100)';
y=sin(x); %response
X=x;
y=y;
% Convert matrix values to double
X = double(X(1:79));
y = double(y(1:79));
% Plot data
plot(X, y, 'rx', 'MarkerSize', 10);
m = length(y);
% Add ones column
X = [ones(m, 1) X];
% Gradient Descent with Normal Equation
theta = (pinv(X'*X))*X'*y
% Predict from 80 till last sample
test_samples = x(80:end);
test_samples_val = [ones(length(test_samples),1) test_samples];
% Calculate predicted value
pred_value = test_samples_val * theta;
X = vertcat(X, test_samples_val);
regressionline = X*theta;
% Plot predicted value with blue cross
plot(test_samples, pred_value, 'bx', 'MarkerSize', 10);
linear-regression prediction matlab matrix
$endgroup$
In the plot below the red crossed line is the actual curve and the crossed blue line is the predicted curve. I am using least squares for linear prediction. I have used 1:79 examples in training and the remaining for testing. The test data points are never seen during training. What is my mistake? Why am I getting such a weird prediction? I want to see the sine curve as the predicted output which should be very close to the original data.
%generate some data
x=linspace(0,2*pi,100)';
y=sin(x); %response
X=x;
y=y;
% Convert matrix values to double
X = double(X(1:79));
y = double(y(1:79));
% Plot data
plot(X, y, 'rx', 'MarkerSize', 10);
m = length(y);
% Add ones column
X = [ones(m, 1) X];
% Gradient Descent with Normal Equation
theta = (pinv(X'*X))*X'*y
% Predict from 80 till last sample
test_samples = x(80:end);
test_samples_val = [ones(length(test_samples),1) test_samples];
% Calculate predicted value
pred_value = test_samples_val * theta;
X = vertcat(X, test_samples_val);
regressionline = X*theta;
% Plot predicted value with blue cross
plot(test_samples, pred_value, 'bx', 'MarkerSize', 10);
linear-regression prediction matlab matrix
linear-regression prediction matlab matrix
asked 4 mins ago
Srishti MSrishti M
2676
2676
add a comment |
add a comment |
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