Why the output data result not the same for Random Forest
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May I know how to modify my Python programming thus it will be get the same result as refer to the attached image file?
import numpy as np
from sklearn import datasets as data
from sklearn.model_selection import train_test_split
from sklearn.tree import DecisionTreeClassifier
from sklearn.ensemble import RandomForestClassifier
from sklearn.metrics import accuracy_score
import matplotlib.pyplot as plt
def load_data(feature_len = 4):
return data.load_iris()['data'][:, :feature_len], data.load_iris()['target']
def tr_te_split(data, target, test_ratio = .2):
return train_test_split(data, target, test_size=test_ratio, random_state=0)
def build_model():
return DecisionTreeClassifier(criterion='entropy'), RandomForestClassifier(criterion='entropy', n_estimators=10, random_state=1)
def train(model, x, y):
model.fit(x, y)
print("{} Training Accuracy = {}".format(str(model.__class__).split('.')[-1].split("'")[0], model.score(x, y)))
return model
def evaluate(model, x, y):
print("{} Testing Accuracy = {}n".format(str(model.__class__).split('.')[-1].split("'")[0], model.score(x, y)))
return accuracy_score(model.predict(x), y)
def main():
data, target = load_data()
tree_score =
rf_score =
for feature_len in range(1, data.shape[-1] + 1):
print("Use {} features.".format(feature_len))
data, target = load_data(feature_len)
x_tr, x_te, y_tr, y_te = tr_te_split(data, target, .4)
tree_model, rf_model = build_model()
tree_model_trained = train(tree_model, x_tr, y_tr)
tree_score.append(evaluate(tree_model_trained, x_te, y_te))
rf_model_trained = train(rf_model, x_tr, y_tr)
rf_score.append(evaluate(rf_model_trained, x_te, y_te))
# draw
tree_plt = plt
tree_plt.plot(tree_score)
tree_plt.xlabel('Number of features')
tree_plt.xticks([0,1,2,3],('1','2','3','4'))
tree_plt.ylabel('Accuracy')
tree_plt.title('Decision Tree')
tree_plt.show()
rf_plt = plt
rf_plt.plot(rf_score)
rf_plt.xlabel('Number of features')
rf_plt.xticks([0,1,2,3],('1','2','3','4'))
rf_plt.ylabel('Accuracy')
plt.yticks(np.arange(0.90, 0.95, 0.01))
rf_plt.title('Ransom Forest')
rf_plt.show()
if __name__ == '__main__':
main()
Please see the image file -

Please help me on this case
machine-learning python random-forest
New contributor
vokoyo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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$begingroup$
May I know how to modify my Python programming thus it will be get the same result as refer to the attached image file?
import numpy as np
from sklearn import datasets as data
from sklearn.model_selection import train_test_split
from sklearn.tree import DecisionTreeClassifier
from sklearn.ensemble import RandomForestClassifier
from sklearn.metrics import accuracy_score
import matplotlib.pyplot as plt
def load_data(feature_len = 4):
return data.load_iris()['data'][:, :feature_len], data.load_iris()['target']
def tr_te_split(data, target, test_ratio = .2):
return train_test_split(data, target, test_size=test_ratio, random_state=0)
def build_model():
return DecisionTreeClassifier(criterion='entropy'), RandomForestClassifier(criterion='entropy', n_estimators=10, random_state=1)
def train(model, x, y):
model.fit(x, y)
print("{} Training Accuracy = {}".format(str(model.__class__).split('.')[-1].split("'")[0], model.score(x, y)))
return model
def evaluate(model, x, y):
print("{} Testing Accuracy = {}n".format(str(model.__class__).split('.')[-1].split("'")[0], model.score(x, y)))
return accuracy_score(model.predict(x), y)
def main():
data, target = load_data()
tree_score =
rf_score =
for feature_len in range(1, data.shape[-1] + 1):
print("Use {} features.".format(feature_len))
data, target = load_data(feature_len)
x_tr, x_te, y_tr, y_te = tr_te_split(data, target, .4)
tree_model, rf_model = build_model()
tree_model_trained = train(tree_model, x_tr, y_tr)
tree_score.append(evaluate(tree_model_trained, x_te, y_te))
rf_model_trained = train(rf_model, x_tr, y_tr)
rf_score.append(evaluate(rf_model_trained, x_te, y_te))
# draw
tree_plt = plt
tree_plt.plot(tree_score)
tree_plt.xlabel('Number of features')
tree_plt.xticks([0,1,2,3],('1','2','3','4'))
tree_plt.ylabel('Accuracy')
tree_plt.title('Decision Tree')
tree_plt.show()
rf_plt = plt
rf_plt.plot(rf_score)
rf_plt.xlabel('Number of features')
rf_plt.xticks([0,1,2,3],('1','2','3','4'))
rf_plt.ylabel('Accuracy')
plt.yticks(np.arange(0.90, 0.95, 0.01))
rf_plt.title('Ransom Forest')
rf_plt.show()
if __name__ == '__main__':
main()
Please see the image file -

Please help me on this case
machine-learning python random-forest
New contributor
vokoyo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
May I know how to modify my Python programming thus it will be get the same result as refer to the attached image file?
import numpy as np
from sklearn import datasets as data
from sklearn.model_selection import train_test_split
from sklearn.tree import DecisionTreeClassifier
from sklearn.ensemble import RandomForestClassifier
from sklearn.metrics import accuracy_score
import matplotlib.pyplot as plt
def load_data(feature_len = 4):
return data.load_iris()['data'][:, :feature_len], data.load_iris()['target']
def tr_te_split(data, target, test_ratio = .2):
return train_test_split(data, target, test_size=test_ratio, random_state=0)
def build_model():
return DecisionTreeClassifier(criterion='entropy'), RandomForestClassifier(criterion='entropy', n_estimators=10, random_state=1)
def train(model, x, y):
model.fit(x, y)
print("{} Training Accuracy = {}".format(str(model.__class__).split('.')[-1].split("'")[0], model.score(x, y)))
return model
def evaluate(model, x, y):
print("{} Testing Accuracy = {}n".format(str(model.__class__).split('.')[-1].split("'")[0], model.score(x, y)))
return accuracy_score(model.predict(x), y)
def main():
data, target = load_data()
tree_score =
rf_score =
for feature_len in range(1, data.shape[-1] + 1):
print("Use {} features.".format(feature_len))
data, target = load_data(feature_len)
x_tr, x_te, y_tr, y_te = tr_te_split(data, target, .4)
tree_model, rf_model = build_model()
tree_model_trained = train(tree_model, x_tr, y_tr)
tree_score.append(evaluate(tree_model_trained, x_te, y_te))
rf_model_trained = train(rf_model, x_tr, y_tr)
rf_score.append(evaluate(rf_model_trained, x_te, y_te))
# draw
tree_plt = plt
tree_plt.plot(tree_score)
tree_plt.xlabel('Number of features')
tree_plt.xticks([0,1,2,3],('1','2','3','4'))
tree_plt.ylabel('Accuracy')
tree_plt.title('Decision Tree')
tree_plt.show()
rf_plt = plt
rf_plt.plot(rf_score)
rf_plt.xlabel('Number of features')
rf_plt.xticks([0,1,2,3],('1','2','3','4'))
rf_plt.ylabel('Accuracy')
plt.yticks(np.arange(0.90, 0.95, 0.01))
rf_plt.title('Ransom Forest')
rf_plt.show()
if __name__ == '__main__':
main()
Please see the image file -

Please help me on this case
machine-learning python random-forest
New contributor
vokoyo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
May I know how to modify my Python programming thus it will be get the same result as refer to the attached image file?
import numpy as np
from sklearn import datasets as data
from sklearn.model_selection import train_test_split
from sklearn.tree import DecisionTreeClassifier
from sklearn.ensemble import RandomForestClassifier
from sklearn.metrics import accuracy_score
import matplotlib.pyplot as plt
def load_data(feature_len = 4):
return data.load_iris()['data'][:, :feature_len], data.load_iris()['target']
def tr_te_split(data, target, test_ratio = .2):
return train_test_split(data, target, test_size=test_ratio, random_state=0)
def build_model():
return DecisionTreeClassifier(criterion='entropy'), RandomForestClassifier(criterion='entropy', n_estimators=10, random_state=1)
def train(model, x, y):
model.fit(x, y)
print("{} Training Accuracy = {}".format(str(model.__class__).split('.')[-1].split("'")[0], model.score(x, y)))
return model
def evaluate(model, x, y):
print("{} Testing Accuracy = {}n".format(str(model.__class__).split('.')[-1].split("'")[0], model.score(x, y)))
return accuracy_score(model.predict(x), y)
def main():
data, target = load_data()
tree_score =
rf_score =
for feature_len in range(1, data.shape[-1] + 1):
print("Use {} features.".format(feature_len))
data, target = load_data(feature_len)
x_tr, x_te, y_tr, y_te = tr_te_split(data, target, .4)
tree_model, rf_model = build_model()
tree_model_trained = train(tree_model, x_tr, y_tr)
tree_score.append(evaluate(tree_model_trained, x_te, y_te))
rf_model_trained = train(rf_model, x_tr, y_tr)
rf_score.append(evaluate(rf_model_trained, x_te, y_te))
# draw
tree_plt = plt
tree_plt.plot(tree_score)
tree_plt.xlabel('Number of features')
tree_plt.xticks([0,1,2,3],('1','2','3','4'))
tree_plt.ylabel('Accuracy')
tree_plt.title('Decision Tree')
tree_plt.show()
rf_plt = plt
rf_plt.plot(rf_score)
rf_plt.xlabel('Number of features')
rf_plt.xticks([0,1,2,3],('1','2','3','4'))
rf_plt.ylabel('Accuracy')
plt.yticks(np.arange(0.90, 0.95, 0.01))
rf_plt.title('Ransom Forest')
rf_plt.show()
if __name__ == '__main__':
main()
Please see the image file -

Please help me on this case
machine-learning python random-forest
machine-learning python random-forest
New contributor
vokoyo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
vokoyo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
vokoyo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
vokoyovokoyo
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New contributor
vokoyo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
vokoyo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
vokoyo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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