I am clueless about caching
0
$begingroup$
Please help me understand what is really going on here? I am clueless. Please explain line by line. I tried reading some articles but still I am unable to understand how they jump from one concept to another.
Where is the change being done for the matrix? What does <<- do and where?
makeCacheMatrix <- function(x = matrix()) {
i <- NULL
set <- function(y) {
x <<- y
i <<- NULL
}
get <- function() x
setinverse <- function(inverse) i <<- inverse
getinverse <- function() i
list(set = set,
get = get,
setinverse = setinverse,
getinverse = getinverse)
}
cacheSolve <- function(x, ...) {
i <- x$getinverse()
if (!is.null(i)) {
message("getting cached data")
return(i)
}
data <- x$get()
i <- solve(data, ...)
x$setinverse(i)
i
}
r matrix
asked 11 mins ago
Mo RahmanMo Rahman
1
New contributor
Mo Rahman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
0
$begingroup$
Please help me understand what is really going on here? I am clueless. Please explain line by line. I tried reading some articles but still I am unable to understand how they jump from one concept to another.
Where is the change being done for the matrix? What does <<- do and where?
makeCacheMatrix <- function(x = matrix()) {
i <- NULL
set <- function(y) {
x <<- y
i <<- NULL
}
get <- function() x
setinverse <- function(inverse) i <<- inverse
getinverse <- function() i
list(set = set,
get = get,
setinverse = setinverse,
getinverse = getinverse)
}
cacheSolve <- function(x, ...) {
i <- x$getinverse()
if (!is.null(i)) {
message("getting cached data")
return(i)
}
data <- x$get()
i <- solve(data, ...)
x$setinverse(i)
i
}
r matrix
asked 11 mins ago
Mo RahmanMo Rahman
1
New contributor
Mo Rahman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
0
0
$begingroup$
Please help me understand what is really going on here? I am clueless. Please explain line by line. I tried reading some articles but still I am unable to understand how they jump from one concept to another.
Where is the change being done for the matrix? What does <<- do and where?
makeCacheMatrix <- function(x = matrix()) {
i <- NULL
set <- function(y) {
x <<- y
i <<- NULL
}
get <- function() x
setinverse <- function(inverse) i <<- inverse
getinverse <- function() i
list(set = set,
get = get,
setinverse = setinverse,
getinverse = getinverse)
}
cacheSolve <- function(x, ...) {
i <- x$getinverse()
if (!is.null(i)) {
message("getting cached data")
return(i)
}
data <- x$get()
i <- solve(data, ...)
x$setinverse(i)
i
}
r matrix
asked 11 mins ago
Mo RahmanMo Rahman
1
New contributor
Mo Rahman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Please help me understand what is really going on here? I am clueless. Please explain line by line. I tried reading some articles but still I am unable to understand how they jump from one concept to another.
Where is the change being done for the matrix? What does <<- do and where?
makeCacheMatrix <- function(x = matrix()) {
i <- NULL
set <- function(y) {
x <<- y
i <<- NULL
}
get <- function() x
setinverse <- function(inverse) i <<- inverse
getinverse <- function() i
list(set = set,
get = get,
setinverse = setinverse,
getinverse = getinverse)
}
cacheSolve <- function(x, ...) {
i <- x$getinverse()
if (!is.null(i)) {
message("getting cached data")
return(i)
}
data <- x$get()
i <- solve(data, ...)
x$setinverse(i)
i
}
r matrix
r matrix
asked 11 mins ago
Mo RahmanMo Rahman
1
New contributor
Mo Rahman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 11 mins ago
Mo RahmanMo Rahman
1
New contributor
Mo Rahman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 11 mins ago
Mo RahmanMo Rahman
1
New contributor
Mo Rahman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 11 mins ago
Mo RahmanMo Rahman
1
asked 11 mins ago
Mo RahmanMo Rahman
1
1
New contributor
Mo Rahman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mo Rahman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Mo Rahman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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