understanding linear algebra of a forget gate












0












$begingroup$


This blog covers the basics of LSTMs -- http://colah.github.io/posts/2015-08-Understanding-LSTMs/.



A forget gate is defined as :



forget gate



At this point the linear algebra confuses me more than it should. The syntax of W*[h,x] is confusing in this context. I think a vector should go into the activation function since the output f is a vector, but the syntax of the forget gate above implies that the input has 2 columns because [h,x] will be an nx2 matrix



For the sake of example lets say ...



W = [ 0 1 
2 3]
h = [ -1
2 ]
x = [ 3
0]
b = [ 1
-2 ]


Can anyone give the final vector that goes into the sigmoid function ?



I think the math is



[ 0 1  [ -1 3      [1    [ 2 0    [ 1   something 
2 3] * 2 0 ] + -2] = 4 6 ] + -2] = wrong









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    0












    $begingroup$


    This blog covers the basics of LSTMs -- http://colah.github.io/posts/2015-08-Understanding-LSTMs/.



    A forget gate is defined as :



    forget gate



    At this point the linear algebra confuses me more than it should. The syntax of W*[h,x] is confusing in this context. I think a vector should go into the activation function since the output f is a vector, but the syntax of the forget gate above implies that the input has 2 columns because [h,x] will be an nx2 matrix



    For the sake of example lets say ...



    W = [ 0 1 
    2 3]
    h = [ -1
    2 ]
    x = [ 3
    0]
    b = [ 1
    -2 ]


    Can anyone give the final vector that goes into the sigmoid function ?



    I think the math is



    [ 0 1  [ -1 3      [1    [ 2 0    [ 1   something 
    2 3] * 2 0 ] + -2] = 4 6 ] + -2] = wrong









    share|improve this question









    New contributor




    sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      0












      0








      0





      $begingroup$


      This blog covers the basics of LSTMs -- http://colah.github.io/posts/2015-08-Understanding-LSTMs/.



      A forget gate is defined as :



      forget gate



      At this point the linear algebra confuses me more than it should. The syntax of W*[h,x] is confusing in this context. I think a vector should go into the activation function since the output f is a vector, but the syntax of the forget gate above implies that the input has 2 columns because [h,x] will be an nx2 matrix



      For the sake of example lets say ...



      W = [ 0 1 
      2 3]
      h = [ -1
      2 ]
      x = [ 3
      0]
      b = [ 1
      -2 ]


      Can anyone give the final vector that goes into the sigmoid function ?



      I think the math is



      [ 0 1  [ -1 3      [1    [ 2 0    [ 1   something 
      2 3] * 2 0 ] + -2] = 4 6 ] + -2] = wrong









      share|improve this question









      New contributor




      sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      This blog covers the basics of LSTMs -- http://colah.github.io/posts/2015-08-Understanding-LSTMs/.



      A forget gate is defined as :



      forget gate



      At this point the linear algebra confuses me more than it should. The syntax of W*[h,x] is confusing in this context. I think a vector should go into the activation function since the output f is a vector, but the syntax of the forget gate above implies that the input has 2 columns because [h,x] will be an nx2 matrix



      For the sake of example lets say ...



      W = [ 0 1 
      2 3]
      h = [ -1
      2 ]
      x = [ 3
      0]
      b = [ 1
      -2 ]


      Can anyone give the final vector that goes into the sigmoid function ?



      I think the math is



      [ 0 1  [ -1 3      [1    [ 2 0    [ 1   something 
      2 3] * 2 0 ] + -2] = 4 6 ] + -2] = wrong






      neural-network lstm rnn






      share|improve this question









      New contributor




      sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 2 mins ago







      sam













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      asked 11 mins ago









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