How to break apart a huge fraction resulting from a symbolic calulation?












2















I'm trying to use a Computer Algebra System to learn something about an algebraic expression, and this is what it gives me as a result in LaTex:



documentclass{article}

usepackage{breqn}



begin{document}



begin{dmath}

    frac{e_{0} n_{0} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) + e_{1} n_{1} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) - e_{10} left(left(- p_{1} + r_{1}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{1} - q_{1}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) - e_{11} left(left(- p_{2} + r_{2}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{2} - q_{2}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) + e_{2} n_{2} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) - e_{9} left(left(- p_{0} + r_{0}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{0} - q_{0}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) + left(e_{3} n_{0} + e_{4} n_{1} + e_{5} n_{2}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right) - left(e_{6} n_{0} + e_{7} n_{1} + e_{8} n_{2}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right)}{left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right)^{2}}

end{dmath}



end{document}


It is a huge fraction, that gets cut when I try to compile this to PDF:



enter image description here



Is there an automagic way to cut this fraction in multiple lines in LaTex? If you look at the LaTex source code, searching for sensible break points to be manually inserted in such expressions will not be fun.



Edit: The fraction looks like this:



enter image description here



You can barely see it, but there is a single denominator, and the numerator is huge. Is there a way to write the numerator automatically across multiple lines?






amsmath fractions breqn







share|improve this question




















  • 3





    Well, this is not a TeX's problem. Tell us how the result should look like and there should be a way how to accomplish this. However, with my typography hat on, there is no good solution that keeps the fraction as a fraction.

    – yo'
    3 hours ago
















2















I'm trying to use a Computer Algebra System to learn something about an algebraic expression, and this is what it gives me as a result in LaTex:



documentclass{article}

usepackage{breqn}



begin{document}



begin{dmath}

    frac{e_{0} n_{0} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) + e_{1} n_{1} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) - e_{10} left(left(- p_{1} + r_{1}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{1} - q_{1}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) - e_{11} left(left(- p_{2} + r_{2}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{2} - q_{2}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) + e_{2} n_{2} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) - e_{9} left(left(- p_{0} + r_{0}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{0} - q_{0}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) + left(e_{3} n_{0} + e_{4} n_{1} + e_{5} n_{2}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right) - left(e_{6} n_{0} + e_{7} n_{1} + e_{8} n_{2}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right)}{left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right)^{2}}

end{dmath}



end{document}


It is a huge fraction, that gets cut when I try to compile this to PDF:



enter image description here



Is there an automagic way to cut this fraction in multiple lines in LaTex? If you look at the LaTex source code, searching for sensible break points to be manually inserted in such expressions will not be fun.



Edit: The fraction looks like this:



enter image description here



You can barely see it, but there is a single denominator, and the numerator is huge. Is there a way to write the numerator automatically across multiple lines?






amsmath fractions breqn







share|improve this question




















  • 3





    Well, this is not a TeX's problem. Tell us how the result should look like and there should be a way how to accomplish this. However, with my typography hat on, there is no good solution that keeps the fraction as a fraction.

    – yo'
    3 hours ago














2












2








2








I'm trying to use a Computer Algebra System to learn something about an algebraic expression, and this is what it gives me as a result in LaTex:



documentclass{article}

usepackage{breqn}



begin{document}



begin{dmath}

    frac{e_{0} n_{0} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) + e_{1} n_{1} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) - e_{10} left(left(- p_{1} + r_{1}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{1} - q_{1}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) - e_{11} left(left(- p_{2} + r_{2}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{2} - q_{2}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) + e_{2} n_{2} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) - e_{9} left(left(- p_{0} + r_{0}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{0} - q_{0}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) + left(e_{3} n_{0} + e_{4} n_{1} + e_{5} n_{2}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right) - left(e_{6} n_{0} + e_{7} n_{1} + e_{8} n_{2}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right)}{left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right)^{2}}

end{dmath}



end{document}


It is a huge fraction, that gets cut when I try to compile this to PDF:



enter image description here



Is there an automagic way to cut this fraction in multiple lines in LaTex? If you look at the LaTex source code, searching for sensible break points to be manually inserted in such expressions will not be fun.



Edit: The fraction looks like this:



enter image description here



You can barely see it, but there is a single denominator, and the numerator is huge. Is there a way to write the numerator automatically across multiple lines?






amsmath fractions breqn







share|improve this question
















I'm trying to use a Computer Algebra System to learn something about an algebraic expression, and this is what it gives me as a result in LaTex:



documentclass{article}

usepackage{breqn}



begin{document}



begin{dmath}

    frac{e_{0} n_{0} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) + e_{1} n_{1} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) - e_{10} left(left(- p_{1} + r_{1}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{1} - q_{1}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) - e_{11} left(left(- p_{2} + r_{2}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{2} - q_{2}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) + e_{2} n_{2} left(- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right)right) - e_{9} left(left(- p_{0} + r_{0}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right) + left(p_{0} - q_{0}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right)right) + left(e_{3} n_{0} + e_{4} n_{1} + e_{5} n_{2}right) left(n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2}right) - left(e_{6} n_{0} + e_{7} n_{1} + e_{8} n_{2}right) left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right)}{left(n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right)right)^{2}}

end{dmath}



end{document}


It is a huge fraction, that gets cut when I try to compile this to PDF:



enter image description here



Is there an automagic way to cut this fraction in multiple lines in LaTex? If you look at the LaTex source code, searching for sensible break points to be manually inserted in such expressions will not be fun.



Edit: The fraction looks like this:



enter image description here



You can barely see it, but there is a single denominator, and the numerator is huge. Is there a way to write the numerator automatically across multiple lines?






amsmath fractions breqn




amsmath fractions breqn






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 3 hours ago







tmaric

















asked 3 hours ago









tmarictmaric

4411416




4411416








  • 3





    Well, this is not a TeX's problem. Tell us how the result should look like and there should be a way how to accomplish this. However, with my typography hat on, there is no good solution that keeps the fraction as a fraction.

    – yo'
    3 hours ago














  • 3





    Well, this is not a TeX's problem. Tell us how the result should look like and there should be a way how to accomplish this. However, with my typography hat on, there is no good solution that keeps the fraction as a fraction.

    – yo'
    3 hours ago








3




3





Well, this is not a TeX's problem. Tell us how the result should look like and there should be a way how to accomplish this. However, with my typography hat on, there is no good solution that keeps the fraction as a fraction.

– yo'
3 hours ago





Well, this is not a TeX's problem. Tell us how the result should look like and there should be a way how to accomplish this. However, with my typography hat on, there is no good solution that keeps the fraction as a fraction.

– yo'
3 hours ago










2 Answers
2






active

oldest

votes


















3














Not automagically. I removed the left and right around long expressions, keeping them only for the differences pi – qi and similar.



documentclass{article}

usepackage{amsmath}



begin{document}



begin{equation}

begin{gathered}

frac{

  ;

  parbox{0.8displaywidth}{raggedrightleftskip=1emhspace{-1em}$

    e_{0} n_{0} (- n_{0} p_{0} + n_{0} r_{0} + n_{0} 

    left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} 

    left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2}

    left(p_{2} - q_{2}right)) + e_{1} n_{1}

    (- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) 

    - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - 

    n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right))

    - e_{10} (left(- p_{1} + r_{1}right) 

   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) 

   + n_{2} left(p_{2} - q_{2}right)) + left(p_{1} - q_{1}right)

   (n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + 

   n_{2} p_{2} - n_{2} r_{2})) 

   - e_{11} (left(- p_{2} + r_{2}right)

   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right)

   + n_{2} left(p_{2} - q_{2}right)) + left(p_{2} - q_{2}right) 

   (n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + 

   n_{2} p_{2} - n_{2} r_{2})) + e_{2} n_{2} 

   (- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) 

   - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right)

   - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right))

   - e_{9} (left(- p_{0} + r_{0}right)

   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right)

   + n_{2} left(p_{2} - q_{2}right))

   + left(p_{0} - q_{0}right) (n_{0} p_{0}

   - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2}

   - n_{2} r_{2})) + (e_{3} n_{0} + e_{4} n_{1}

   + e_{5} n_{2}) (n_{0} p_{0} - n_{0} r_{0}

   + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2})

   - (e_{6} n_{0} + e_{7} n_{1} + e_{8} n_{2})

   (n_{0} left(p_{0} - q_{0}right) + n_{1}

   left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right))

  $};

}{

  (n_{0} (p_{0} - q_{0}) + n_{1} (p_{1} - q_{1}) + n_{2} (p_{2} - q_{2}))^{2}

}

end{gathered}

end{equation}



end{document}


enter image description here






share|improve this answer































    3














    Not automagically, I'm afraid. First and foremost, don't use left and right sizing directives: Not only do they not succeed in enlarging any of the parentheses, they also prevent TeX from inserting line breaks within the scope of left-right pairs. Second, use a parbox directive, and typeset the equation in inline-math mode (no frac terms) inside the parbox. Why inline-math mode? Because TeX allows line-breaking for inline-math material (as long as there are no left-right disturbances).



    To set off the start and end of the numerator and denominator term, use curly braces .



    Optionally, use square brackets -- [ and and ] -- instead of the "outer" round parentheses.



    That said, I'm not sure what your readers are supposed to take away -- let alone remember for more than three seconds -- from looking at the following expression...



    enter image description here



    documentclass{article}
    
begin{document}
    

    
[ 
    
parbox{0.8textwidth}{$bigl{
    
  e_0 n_0 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
    
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
    
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
    
+ e_1 n_1 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
    
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
    
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
    
- e_{10} [(- p_1 + r_1) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
    
          + (p_1 - q_1) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
    
- e_{11} [(- p_2 + r_2) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
    
          + (p_2 - q_2) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
    
+ e_2 n_2 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
    
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
    
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
    
- e_9 [(- p_0 + r_0) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
    
       + (p_0 - q_0) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
    
+ [e_3 n_0 + e_4 n_1 + e_5 n_2] [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)] 
    
- [e_6 n_0 + e_7 n_1 + e_8 n_2] [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)]
    
bigr}big/bigl{
    
n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)
    
bigr}^2 $}
    
]
    

    
end{document}





    share|improve this answer

























      Your Answer








      StackExchange.ready(function() {
      var channelOptions = {
      tags: "".split(" "),
      id: "85"
      };
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function() {
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled) {
      StackExchange.using("snippets", function() {
      createEditor();
      });
      }
      else {
      createEditor();
      }
      });

      function createEditor() {
      StackExchange.prepareEditor({
      heartbeatType: 'answer',
      autoActivateHeartbeat: false,
      convertImagesToLinks: false,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: null,
      bindNavPrevention: true,
      postfix: "",
      imageUploader: {
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      },
      onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      });


      }
      });














      draft saved

      draft discarded


















      StackExchange.ready(
      function () {
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f471280%2fhow-to-break-apart-a-huge-fraction-resulting-from-a-symbolic-calulation%23new-answer', 'question_page');
      }
      );

      Post as a guest















      Required, but never shown

























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3














      Not automagically. I removed the left and right around long expressions, keeping them only for the differences pi – qi and similar.



      documentclass{article}
      
usepackage{amsmath}
      

      
begin{document}
      

      
begin{equation}
      
begin{gathered}
      
frac{
      
  ;
      
  parbox{0.8displaywidth}{raggedrightleftskip=1emhspace{-1em}$
      
    e_{0} n_{0} (- n_{0} p_{0} + n_{0} r_{0} + n_{0} 
      
    left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} 
      
    left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2}
      
    left(p_{2} - q_{2}right)) + e_{1} n_{1}
      
    (- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) 
      
    - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - 
      
    n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right))
      
    - e_{10} (left(- p_{1} + r_{1}right) 
      
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) 
      
   + n_{2} left(p_{2} - q_{2}right)) + left(p_{1} - q_{1}right)
      
   (n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + 
      
   n_{2} p_{2} - n_{2} r_{2})) 
      
   - e_{11} (left(- p_{2} + r_{2}right)
      
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right)
      
   + n_{2} left(p_{2} - q_{2}right)) + left(p_{2} - q_{2}right) 
      
   (n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + 
      
   n_{2} p_{2} - n_{2} r_{2})) + e_{2} n_{2} 
      
   (- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) 
      
   - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right)
      
   - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right))
      
   - e_{9} (left(- p_{0} + r_{0}right)
      
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right)
      
   + n_{2} left(p_{2} - q_{2}right))
      
   + left(p_{0} - q_{0}right) (n_{0} p_{0}
      
   - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2}
      
   - n_{2} r_{2})) + (e_{3} n_{0} + e_{4} n_{1}
      
   + e_{5} n_{2}) (n_{0} p_{0} - n_{0} r_{0}
      
   + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2})
      
   - (e_{6} n_{0} + e_{7} n_{1} + e_{8} n_{2})
      
   (n_{0} left(p_{0} - q_{0}right) + n_{1}
      
   left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right))
      
  $};
      
}{
      
  (n_{0} (p_{0} - q_{0}) + n_{1} (p_{1} - q_{1}) + n_{2} (p_{2} - q_{2}))^{2}
      
}
      
end{gathered}
      
end{equation}
      

      
end{document}


      enter image description here






      share|improve this answer




























        3














        Not automagically. I removed the left and right around long expressions, keeping them only for the differences pi – qi and similar.



        documentclass{article}
        
usepackage{amsmath}
        

        
begin{document}
        

        
begin{equation}
        
begin{gathered}
        
frac{
        
  ;
        
  parbox{0.8displaywidth}{raggedrightleftskip=1emhspace{-1em}$
        
    e_{0} n_{0} (- n_{0} p_{0} + n_{0} r_{0} + n_{0} 
        
    left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} 
        
    left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2}
        
    left(p_{2} - q_{2}right)) + e_{1} n_{1}
        
    (- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) 
        
    - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - 
        
    n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right))
        
    - e_{10} (left(- p_{1} + r_{1}right) 
        
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) 
        
   + n_{2} left(p_{2} - q_{2}right)) + left(p_{1} - q_{1}right)
        
   (n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + 
        
   n_{2} p_{2} - n_{2} r_{2})) 
        
   - e_{11} (left(- p_{2} + r_{2}right)
        
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right)
        
   + n_{2} left(p_{2} - q_{2}right)) + left(p_{2} - q_{2}right) 
        
   (n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + 
        
   n_{2} p_{2} - n_{2} r_{2})) + e_{2} n_{2} 
        
   (- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) 
        
   - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right)
        
   - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right))
        
   - e_{9} (left(- p_{0} + r_{0}right)
        
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right)
        
   + n_{2} left(p_{2} - q_{2}right))
        
   + left(p_{0} - q_{0}right) (n_{0} p_{0}
        
   - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2}
        
   - n_{2} r_{2})) + (e_{3} n_{0} + e_{4} n_{1}
        
   + e_{5} n_{2}) (n_{0} p_{0} - n_{0} r_{0}
        
   + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2})
        
   - (e_{6} n_{0} + e_{7} n_{1} + e_{8} n_{2})
        
   (n_{0} left(p_{0} - q_{0}right) + n_{1}
        
   left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right))
        
  $};
        
}{
        
  (n_{0} (p_{0} - q_{0}) + n_{1} (p_{1} - q_{1}) + n_{2} (p_{2} - q_{2}))^{2}
        
}
        
end{gathered}
        
end{equation}
        

        
end{document}


        enter image description here






        share|improve this answer


























          3












          3








          3







          Not automagically. I removed the left and right around long expressions, keeping them only for the differences pi – qi and similar.



          documentclass{article}
          
usepackage{amsmath}
          

          
begin{document}
          

          
begin{equation}
          
begin{gathered}
          
frac{
          
  ;
          
  parbox{0.8displaywidth}{raggedrightleftskip=1emhspace{-1em}$
          
    e_{0} n_{0} (- n_{0} p_{0} + n_{0} r_{0} + n_{0} 
          
    left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} 
          
    left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2}
          
    left(p_{2} - q_{2}right)) + e_{1} n_{1}
          
    (- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) 
          
    - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - 
          
    n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right))
          
    - e_{10} (left(- p_{1} + r_{1}right) 
          
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) 
          
   + n_{2} left(p_{2} - q_{2}right)) + left(p_{1} - q_{1}right)
          
   (n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + 
          
   n_{2} p_{2} - n_{2} r_{2})) 
          
   - e_{11} (left(- p_{2} + r_{2}right)
          
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right)
          
   + n_{2} left(p_{2} - q_{2}right)) + left(p_{2} - q_{2}right) 
          
   (n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + 
          
   n_{2} p_{2} - n_{2} r_{2})) + e_{2} n_{2} 
          
   (- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) 
          
   - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right)
          
   - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right))
          
   - e_{9} (left(- p_{0} + r_{0}right)
          
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right)
          
   + n_{2} left(p_{2} - q_{2}right))
          
   + left(p_{0} - q_{0}right) (n_{0} p_{0}
          
   - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2}
          
   - n_{2} r_{2})) + (e_{3} n_{0} + e_{4} n_{1}
          
   + e_{5} n_{2}) (n_{0} p_{0} - n_{0} r_{0}
          
   + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2})
          
   - (e_{6} n_{0} + e_{7} n_{1} + e_{8} n_{2})
          
   (n_{0} left(p_{0} - q_{0}right) + n_{1}
          
   left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right))
          
  $};
          
}{
          
  (n_{0} (p_{0} - q_{0}) + n_{1} (p_{1} - q_{1}) + n_{2} (p_{2} - q_{2}))^{2}
          
}
          
end{gathered}
          
end{equation}
          

          
end{document}


          enter image description here






          share|improve this answer













          Not automagically. I removed the left and right around long expressions, keeping them only for the differences pi – qi and similar.



          documentclass{article}
          
usepackage{amsmath}
          

          
begin{document}
          

          
begin{equation}
          
begin{gathered}
          
frac{
          
  ;
          
  parbox{0.8displaywidth}{raggedrightleftskip=1emhspace{-1em}$
          
    e_{0} n_{0} (- n_{0} p_{0} + n_{0} r_{0} + n_{0} 
          
    left(p_{0} - q_{0}right) - n_{1} p_{1} + n_{1} r_{1} + n_{1} 
          
    left(p_{1} - q_{1}right) - n_{2} p_{2} + n_{2} r_{2} + n_{2}
          
    left(p_{2} - q_{2}right)) + e_{1} n_{1}
          
    (- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) 
          
    - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right) - 
          
    n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right))
          
    - e_{10} (left(- p_{1} + r_{1}right) 
          
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right) 
          
   + n_{2} left(p_{2} - q_{2}right)) + left(p_{1} - q_{1}right)
          
   (n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + 
          
   n_{2} p_{2} - n_{2} r_{2})) 
          
   - e_{11} (left(- p_{2} + r_{2}right)
          
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right)
          
   + n_{2} left(p_{2} - q_{2}right)) + left(p_{2} - q_{2}right) 
          
   (n_{0} p_{0} - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + 
          
   n_{2} p_{2} - n_{2} r_{2})) + e_{2} n_{2} 
          
   (- n_{0} p_{0} + n_{0} r_{0} + n_{0} left(p_{0} - q_{0}right) 
          
   - n_{1} p_{1} + n_{1} r_{1} + n_{1} left(p_{1} - q_{1}right)
          
   - n_{2} p_{2} + n_{2} r_{2} + n_{2} left(p_{2} - q_{2}right))
          
   - e_{9} (left(- p_{0} + r_{0}right)
          
   (n_{0} left(p_{0} - q_{0}right) + n_{1} left(p_{1} - q_{1}right)
          
   + n_{2} left(p_{2} - q_{2}right))
          
   + left(p_{0} - q_{0}right) (n_{0} p_{0}
          
   - n_{0} r_{0} + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2}
          
   - n_{2} r_{2})) + (e_{3} n_{0} + e_{4} n_{1}
          
   + e_{5} n_{2}) (n_{0} p_{0} - n_{0} r_{0}
          
   + n_{1} p_{1} - n_{1} r_{1} + n_{2} p_{2} - n_{2} r_{2})
          
   - (e_{6} n_{0} + e_{7} n_{1} + e_{8} n_{2})
          
   (n_{0} left(p_{0} - q_{0}right) + n_{1}
          
   left(p_{1} - q_{1}right) + n_{2} left(p_{2} - q_{2}right))
          
  $};
          
}{
          
  (n_{0} (p_{0} - q_{0}) + n_{1} (p_{1} - q_{1}) + n_{2} (p_{2} - q_{2}))^{2}
          
}
          
end{gathered}
          
end{equation}
          

          
end{document}


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 3 hours ago









          egregegreg

          714k8618973184




          714k8618973184























              3














              Not automagically, I'm afraid. First and foremost, don't use left and right sizing directives: Not only do they not succeed in enlarging any of the parentheses, they also prevent TeX from inserting line breaks within the scope of left-right pairs. Second, use a parbox directive, and typeset the equation in inline-math mode (no frac terms) inside the parbox. Why inline-math mode? Because TeX allows line-breaking for inline-math material (as long as there are no left-right disturbances).



              To set off the start and end of the numerator and denominator term, use curly braces .



              Optionally, use square brackets -- [ and and ] -- instead of the "outer" round parentheses.



              That said, I'm not sure what your readers are supposed to take away -- let alone remember for more than three seconds -- from looking at the following expression...



              enter image description here



              documentclass{article}
              
begin{document}
              

              
[ 
              
parbox{0.8textwidth}{$bigl{
              
  e_0 n_0 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
              
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
              
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
              
+ e_1 n_1 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
              
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
              
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
              
- e_{10} [(- p_1 + r_1) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
              
          + (p_1 - q_1) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
              
- e_{11} [(- p_2 + r_2) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
              
          + (p_2 - q_2) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
              
+ e_2 n_2 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
              
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
              
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
              
- e_9 [(- p_0 + r_0) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
              
       + (p_0 - q_0) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
              
+ [e_3 n_0 + e_4 n_1 + e_5 n_2] [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)] 
              
- [e_6 n_0 + e_7 n_1 + e_8 n_2] [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)]
              
bigr}big/bigl{
              
n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)
              
bigr}^2 $}
              
]
              

              
end{document}





              share|improve this answer






























                3














                Not automagically, I'm afraid. First and foremost, don't use left and right sizing directives: Not only do they not succeed in enlarging any of the parentheses, they also prevent TeX from inserting line breaks within the scope of left-right pairs. Second, use a parbox directive, and typeset the equation in inline-math mode (no frac terms) inside the parbox. Why inline-math mode? Because TeX allows line-breaking for inline-math material (as long as there are no left-right disturbances).



                To set off the start and end of the numerator and denominator term, use curly braces .



                Optionally, use square brackets -- [ and and ] -- instead of the "outer" round parentheses.



                That said, I'm not sure what your readers are supposed to take away -- let alone remember for more than three seconds -- from looking at the following expression...



                enter image description here



                documentclass{article}
                
begin{document}
                

                
[ 
                
parbox{0.8textwidth}{$bigl{
                
  e_0 n_0 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
                
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
                
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
                
+ e_1 n_1 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
                
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
                
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
                
- e_{10} [(- p_1 + r_1) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
                
          + (p_1 - q_1) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
                
- e_{11} [(- p_2 + r_2) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
                
          + (p_2 - q_2) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
                
+ e_2 n_2 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
                
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
                
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
                
- e_9 [(- p_0 + r_0) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
                
       + (p_0 - q_0) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
                
+ [e_3 n_0 + e_4 n_1 + e_5 n_2] [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)] 
                
- [e_6 n_0 + e_7 n_1 + e_8 n_2] [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)]
                
bigr}big/bigl{
                
n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)
                
bigr}^2 $}
                
]
                

                
end{document}





                share|improve this answer




























                  3












                  3








                  3







                  Not automagically, I'm afraid. First and foremost, don't use left and right sizing directives: Not only do they not succeed in enlarging any of the parentheses, they also prevent TeX from inserting line breaks within the scope of left-right pairs. Second, use a parbox directive, and typeset the equation in inline-math mode (no frac terms) inside the parbox. Why inline-math mode? Because TeX allows line-breaking for inline-math material (as long as there are no left-right disturbances).



                  To set off the start and end of the numerator and denominator term, use curly braces .



                  Optionally, use square brackets -- [ and and ] -- instead of the "outer" round parentheses.



                  That said, I'm not sure what your readers are supposed to take away -- let alone remember for more than three seconds -- from looking at the following expression...



                  enter image description here



                  documentclass{article}
                  
begin{document}
                  

                  
[ 
                  
parbox{0.8textwidth}{$bigl{
                  
  e_0 n_0 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
                  
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
                  
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
                  
+ e_1 n_1 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
                  
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
                  
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
                  
- e_{10} [(- p_1 + r_1) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
                  
          + (p_1 - q_1) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
                  
- e_{11} [(- p_2 + r_2) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
                  
          + (p_2 - q_2) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
                  
+ e_2 n_2 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
                  
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
                  
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
                  
- e_9 [(- p_0 + r_0) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
                  
       + (p_0 - q_0) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
                  
+ [e_3 n_0 + e_4 n_1 + e_5 n_2] [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)] 
                  
- [e_6 n_0 + e_7 n_1 + e_8 n_2] [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)]
                  
bigr}big/bigl{
                  
n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)
                  
bigr}^2 $}
                  
]
                  

                  
end{document}





                  share|improve this answer















                  Not automagically, I'm afraid. First and foremost, don't use left and right sizing directives: Not only do they not succeed in enlarging any of the parentheses, they also prevent TeX from inserting line breaks within the scope of left-right pairs. Second, use a parbox directive, and typeset the equation in inline-math mode (no frac terms) inside the parbox. Why inline-math mode? Because TeX allows line-breaking for inline-math material (as long as there are no left-right disturbances).



                  To set off the start and end of the numerator and denominator term, use curly braces .



                  Optionally, use square brackets -- [ and and ] -- instead of the "outer" round parentheses.



                  That said, I'm not sure what your readers are supposed to take away -- let alone remember for more than three seconds -- from looking at the following expression...



                  enter image description here



                  documentclass{article}
                  
begin{document}
                  

                  
[ 
                  
parbox{0.8textwidth}{$bigl{
                  
  e_0 n_0 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
                  
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
                  
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
                  
+ e_1 n_1 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
                  
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
                  
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
                  
- e_{10} [(- p_1 + r_1) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
                  
          + (p_1 - q_1) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
                  
- e_{11} [(- p_2 + r_2) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
                  
          + (p_2 - q_2) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
                  
+ e_2 n_2 [- n_0 (p_0 - r_0) + n_0 (p_0 - q_0) 
                  
           - n_1 (p_1 - r_1) + n_1 (p_1 - q_1) 
                  
           - n_2 (p_2 - r_2) + n_2 (p_2 - q_2)] 
                  
- e_9 [(- p_0 + r_0) [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)] 
                  
       + (p_0 - q_0) [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)]] 
                  
+ [e_3 n_0 + e_4 n_1 + e_5 n_2] [n_0 (p_0 - r_0) + n_1 (p_1 - r_1) + n_2 (p_2 - r_2)] 
                  
- [e_6 n_0 + e_7 n_1 + e_8 n_2] [n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)]
                  
bigr}big/bigl{
                  
n_0 (p_0 - q_0) + n_1 (p_1 - q_1) + n_2 (p_2 - q_2)
                  
bigr}^2 $}
                  
]
                  

                  
end{document}






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 2 hours ago

























                  answered 3 hours ago









                  MicoMico

                  276k30374763




                  276k30374763






























                      draft saved

                      draft discarded




















































                      Thanks for contributing an answer to TeX - LaTeX Stack Exchange!


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid …



                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.


                      To learn more, see our tips on writing great answers.




                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function () {
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f471280%2fhow-to-break-apart-a-huge-fraction-resulting-from-a-symbolic-calulation%23new-answer', 'question_page');
                      }
                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      -

                      Popular posts from this blog

                      Ponta tanko

                      Image
                      Usona ponta tanko M60A1 Ponta tanko estas, simile kiel kirasita savveturilo, inter specialaj kirasitaj transportiloj. Kiel pontaj tankoj eblas konsideri ĉiujn memmovigaj rimedoj ebligantaj superi obstaklojn ĝis larĝeco 24 metroj rekte en spaco de bataloperacoj. Ties ĉefa tasko estas ebligi al la propraj taĉmentoj daŭrigi en rapida antaŭenirado sen senbezona reteniĝo. El tio pli-malpli rezultas taktikaj-teknikaj postuloj, kiujn ili devas plenumi. Precipe temas pri kapablo operacii komune kun unue-sinsekvaj taĉmentoj kaj transpontigi obstaklojn dum kelke da minutoj. This page is only for reference, If you need detailed information, please check here
                      Read more

                      Tantalo (mitologio)

                      Image
                      Ĉi tiu artikolo temas pri mitologio. Por aliaj signifoj vidu la paĝon Tantalo (apartigilo) . Tantalo , laŭ Gioacchino Assereto. Laŭ la helena mitologio, Tantalo (el la greka Τάνταλος , ŝancelanta aŭ tre malfeliĉa ) estis filo de Zeŭso kaj la oceanidino Pluto, laŭ la plej divastigata versio. Li estis reĝo de Frigio [1] aŭ de la monto Sipilo, en Lidio (Malgrandazio) [2] kaj post sia morto li suferis eternan torturadon ĉe la Tartaro, la plej profunda parto de Hadeso, rezervita por la plej perversaj homoj. Tamen, kelkaj rakontoj asertas ke li estis reĝo de Argo aŭ de Korinto [3] , aŭ ke li migris norden el la monto Sipilo por akiri la tronon de Paflagonio, el kie Ilo forpelis lin pro tio, ke Tantalo forkaptis kaj seksperfortis lian fraton Ganimedon [4] , kaj tiel ofendis la diojn. Verŝajne li ankaŭ regis urbon en okcidenta Anatolio, kiun oni nomis Tantalis [5] pro li, aŭ Sipilo , pro la monto sur kies flanko ankoraŭ staras ĝiaj ruinaĵoj [6] . Laŭ la geografiisto Strabo,...
                      Read more

                      Erzsébet Schaár

                      Image
                      Erzsébet Schaár Memportreto de Erzsébet Schaár en Pécs Personaj informoj Naskiĝo 27-an de julio 1908 ( 1908-07-27 ) en Budafok Morto 29-an de aŭgusto 1975 ( 1975-08-29 ) (67-jara) en Budapeŝto Ŝtataneco Hungario Profesio skulptisto Familianoj Edz(in)o Tibor Vilt v   •   d   •   r Erzsébet Schaár [erĵEbet ŝAr], laŭ hungarlingve kutima sinsekvo Schaár Erzsébet estis hungara skulptisto. Ŝia edzo estis Tibor Vilt. Déryné Széppataki Róza en Miskolc fare de Erzsébet Schaár Erzsébet Schaár [1] naskiĝis la 27-an de julio 1908 en Budafok, ŝi mortis la 29-an de aŭgusto 1975 en Budapeŝto. Enhavo 1 Biografio 2 Elektitaj solaj ekspozicioj 3 Elektitaj kolektivaj ekspozicioj 4 Elektitaj skulptaĵoj 5 Elektitaj disĉiploj 6 Fontoj 7 Referencoj Biografio | Erzsébet Schaár studis en Industriarta Lernejo, poste en Reĝa Belarta Altlernejo (1924-1926). Ŝia ĉefinstruisto estis Zsig...
                      Read more