Converting a text file to Map<String, List> using lambda
7
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>> by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
edited 3 hours ago
Deadpool
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
7
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>> by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
edited 3 hours ago
Deadpool
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
add a comment |
7
7
7
1
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>> by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
edited 3 hours ago
Deadpool
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>> by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
java java-8 java-stream
edited 3 hours ago
Deadpool
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 3 hours ago
Deadpool
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 3 hours ago
Deadpool
5,1822528
edited 3 hours ago
Deadpool
5,1822528
edited 3 hours ago
Deadpool
5,1822528
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
BartDBartD
383
asked 3 hours ago
BartDBartD
383
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
add a comment |
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
2
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
add a comment |
3 Answers
3
active
oldest
votes
3
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collectdocumentation
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
add a comment |
2
Use Collectors.mapping while groupingBy, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
answered 3 hours ago
DeadpoolDeadpool
5,1822528
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
0
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.
Note: I am a committer for Eclipse Collections.
answered 19 mins ago
Donald RaabDonald Raab
4,26112029
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collectdocumentation
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
add a comment |
3
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collectdocumentation
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
add a comment |
3
3
3
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collectdocumentation
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collectdocumentation
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
edited 3 hours ago
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
12.9k967101
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
add a comment |
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
add a comment |
2
Use Collectors.mapping while groupingBy, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
answered 3 hours ago
DeadpoolDeadpool
5,1822528
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
2
Use Collectors.mapping while groupingBy, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
answered 3 hours ago
DeadpoolDeadpool
5,1822528
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
2
2
2
Use Collectors.mapping while groupingBy, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
answered 3 hours ago
DeadpoolDeadpool
5,1822528
Use Collectors.mapping while groupingBy, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
answered 3 hours ago
DeadpoolDeadpool
5,1822528
edited 3 hours ago
answered 3 hours ago
DeadpoolDeadpool
5,1822528
answered 3 hours ago
DeadpoolDeadpool
5,1822528
answered 3 hours ago
DeadpoolDeadpool
5,1822528
5,1822528
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
1
1
That is exactly what I was looking for!
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList()))); and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2– BartD
3 hours ago
That is exactly what I was looking for!
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList()))); and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2– BartD
3 hours ago
add a comment |
0
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.
Note: I am a committer for Eclipse Collections.
answered 19 mins ago
Donald RaabDonald Raab
4,26112029
add a comment |
0
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.
Note: I am a committer for Eclipse Collections.
answered 19 mins ago
Donald RaabDonald Raab
4,26112029
add a comment |
0
0
0
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.
Note: I am a committer for Eclipse Collections.
answered 19 mins ago
Donald RaabDonald Raab
4,26112029
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.
Note: I am a committer for Eclipse Collections.
answered 19 mins ago
Donald RaabDonald Raab
4,26112029
answered 19 mins ago
Donald RaabDonald Raab
4,26112029
answered 19 mins ago
Donald RaabDonald Raab
4,26112029
answered 19 mins ago
Donald RaabDonald Raab
4,26112029
4,26112029
add a comment |
add a comment |
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BartD is a new contributor. Be nice, and check out our Code of Conduct.
BartD is a new contributor. Be nice, and check out our Code of Conduct.
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2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago