Frequency Response
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How to plot frequency response which includes magnitude response and phase response of a transfer function in Mathematica?
In Matlab, we can use [h,k]=freqz(b, a, N); to generate magnitude response we can plot abs(h) and to plot phase we can do it by angle(h).
So is there any kind of alternative for this Mathematica?
Example : 2y(n-2)+5y(n-1)+7y(n) = 3x(n-1)+5x(n)
matlab mathematica-online grid-mathematica
asked 1 hour ago
Ajay DyavathiAjay Dyavathi
62
New contributor
Ajay Dyavathi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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add a comment |
$begingroup$
How to plot frequency response which includes magnitude response and phase response of a transfer function in Mathematica?
In Matlab, we can use [h,k]=freqz(b, a, N); to generate magnitude response we can plot abs(h) and to plot phase we can do it by angle(h).
So is there any kind of alternative for this Mathematica?
Example : 2y(n-2)+5y(n-1)+7y(n) = 3x(n-1)+5x(n)
matlab mathematica-online grid-mathematica
asked 1 hour ago
Ajay DyavathiAjay Dyavathi
62
New contributor
Ajay Dyavathi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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Welcome to Mathematica SE. If you want good answers, please provide a minimal example of a differential equation so that people can demonstrate Mathematica's capabilities more concretely.
$endgroup$
– Roman
1 hour ago
add a comment |
$begingroup$
How to plot frequency response which includes magnitude response and phase response of a transfer function in Mathematica?
In Matlab, we can use [h,k]=freqz(b, a, N); to generate magnitude response we can plot abs(h) and to plot phase we can do it by angle(h).
So is there any kind of alternative for this Mathematica?
Example : 2y(n-2)+5y(n-1)+7y(n) = 3x(n-1)+5x(n)
matlab mathematica-online grid-mathematica
asked 1 hour ago
Ajay DyavathiAjay Dyavathi
62
New contributor
Ajay Dyavathi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
How to plot frequency response which includes magnitude response and phase response of a transfer function in Mathematica?
In Matlab, we can use [h,k]=freqz(b, a, N); to generate magnitude response we can plot abs(h) and to plot phase we can do it by angle(h).
So is there any kind of alternative for this Mathematica?
Example : 2y(n-2)+5y(n-1)+7y(n) = 3x(n-1)+5x(n)
matlab mathematica-online grid-mathematica
matlab mathematica-online grid-mathematica
asked 1 hour ago
Ajay DyavathiAjay Dyavathi
62
New contributor
Ajay Dyavathi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
Ajay DyavathiAjay Dyavathi
62
New contributor
Ajay Dyavathi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Ajay Dyavathi
asked 1 hour ago
Ajay DyavathiAjay Dyavathi
62
New contributor
Ajay Dyavathi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
Ajay DyavathiAjay Dyavathi
62
asked 1 hour ago
Ajay DyavathiAjay Dyavathi
62
62
New contributor
Ajay Dyavathi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Ajay Dyavathi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Ajay Dyavathi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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Welcome to Mathematica SE. If you want good answers, please provide a minimal example of a differential equation so that people can demonstrate Mathematica's capabilities more concretely.
$endgroup$
– Roman
1 hour ago
add a comment |
$begingroup$
Welcome to Mathematica SE. If you want good answers, please provide a minimal example of a differential equation so that people can demonstrate Mathematica's capabilities more concretely.
$endgroup$
– Roman
1 hour ago
$begingroup$
Welcome to Mathematica SE. If you want good answers, please provide a minimal example of a differential equation so that people can demonstrate Mathematica's capabilities more concretely.
$endgroup$
– Roman
1 hour ago
$begingroup$
Welcome to Mathematica SE. If you want good answers, please provide a minimal example of a differential equation so that people can demonstrate Mathematica's capabilities more concretely.
$endgroup$
– Roman
1 hour ago
add a comment |
1 Answer
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oldest
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In Mathematica, you can work with the function h(z) directly, since Mathematica is symbolic based. In other words, while in Matlab one needs to work for numerical values of coefficients of numerator and denominator and make sure they are in the correct order and so on, in Mathematica, you work with the actual formula or expression itself (transfer function, either in s or z domain).
I just looked at example in Matlab home page for freqz, which used [h,w] = freqz(b,a,'whole',2001); and duplicated the output. This just gives you a start.
In Mathematica:
The code is
h[z_] := (0.05634*(1 + 1/z)*(1 - 1.0166/z + 1/z^2))/((1 -
0.683/z)*(1 - 1.4461/z + 0.7957/z^2));
sys = TransferFunctionModel[h[z], z, SamplingPeriod -> 1];
BodePlot[sys, {0.43, 6}]
There are many options you can adjust for scaling and units and such. See BodePlot and TransferFunctionModel
answered 38 mins ago
NasserNasser
59.1k491208
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
In Mathematica, you can work with the function h(z) directly, since Mathematica is symbolic based. In other words, while in Matlab one needs to work for numerical values of coefficients of numerator and denominator and make sure they are in the correct order and so on, in Mathematica, you work with the actual formula or expression itself (transfer function, either in s or z domain).
I just looked at example in Matlab home page for freqz, which used [h,w] = freqz(b,a,'whole',2001); and duplicated the output. This just gives you a start.
In Mathematica:
The code is
h[z_] := (0.05634*(1 + 1/z)*(1 - 1.0166/z + 1/z^2))/((1 -
0.683/z)*(1 - 1.4461/z + 0.7957/z^2));
sys = TransferFunctionModel[h[z], z, SamplingPeriod -> 1];
BodePlot[sys, {0.43, 6}]
There are many options you can adjust for scaling and units and such. See BodePlot and TransferFunctionModel
answered 38 mins ago
NasserNasser
59.1k491208
$endgroup$
add a comment |
$begingroup$
In Mathematica, you can work with the function h(z) directly, since Mathematica is symbolic based. In other words, while in Matlab one needs to work for numerical values of coefficients of numerator and denominator and make sure they are in the correct order and so on, in Mathematica, you work with the actual formula or expression itself (transfer function, either in s or z domain).
I just looked at example in Matlab home page for freqz, which used [h,w] = freqz(b,a,'whole',2001); and duplicated the output. This just gives you a start.
In Mathematica:
The code is
h[z_] := (0.05634*(1 + 1/z)*(1 - 1.0166/z + 1/z^2))/((1 -
0.683/z)*(1 - 1.4461/z + 0.7957/z^2));
sys = TransferFunctionModel[h[z], z, SamplingPeriod -> 1];
BodePlot[sys, {0.43, 6}]
There are many options you can adjust for scaling and units and such. See BodePlot and TransferFunctionModel
answered 38 mins ago
NasserNasser
59.1k491208
$endgroup$
add a comment |
$begingroup$
In Mathematica, you can work with the function h(z) directly, since Mathematica is symbolic based. In other words, while in Matlab one needs to work for numerical values of coefficients of numerator and denominator and make sure they are in the correct order and so on, in Mathematica, you work with the actual formula or expression itself (transfer function, either in s or z domain).
I just looked at example in Matlab home page for freqz, which used [h,w] = freqz(b,a,'whole',2001); and duplicated the output. This just gives you a start.
In Mathematica:
The code is
h[z_] := (0.05634*(1 + 1/z)*(1 - 1.0166/z + 1/z^2))/((1 -
0.683/z)*(1 - 1.4461/z + 0.7957/z^2));
sys = TransferFunctionModel[h[z], z, SamplingPeriod -> 1];
BodePlot[sys, {0.43, 6}]
There are many options you can adjust for scaling and units and such. See BodePlot and TransferFunctionModel
answered 38 mins ago
NasserNasser
59.1k491208
$endgroup$
In Mathematica, you can work with the function h(z) directly, since Mathematica is symbolic based. In other words, while in Matlab one needs to work for numerical values of coefficients of numerator and denominator and make sure they are in the correct order and so on, in Mathematica, you work with the actual formula or expression itself (transfer function, either in s or z domain).
I just looked at example in Matlab home page for freqz, which used [h,w] = freqz(b,a,'whole',2001); and duplicated the output. This just gives you a start.
In Mathematica:
The code is
h[z_] := (0.05634*(1 + 1/z)*(1 - 1.0166/z + 1/z^2))/((1 -
0.683/z)*(1 - 1.4461/z + 0.7957/z^2));
sys = TransferFunctionModel[h[z], z, SamplingPeriod -> 1];
BodePlot[sys, {0.43, 6}]
There are many options you can adjust for scaling and units and such. See BodePlot and TransferFunctionModel
answered 38 mins ago
NasserNasser
59.1k491208
edited 27 mins ago
answered 38 mins ago
NasserNasser
59.1k491208
answered 38 mins ago
NasserNasser
59.1k491208
answered 38 mins ago
NasserNasser
59.1k491208
59.1k491208
add a comment |
add a comment |
Ajay Dyavathi is a new contributor. Be nice, and check out our Code of Conduct.
Ajay Dyavathi is a new contributor. Be nice, and check out our Code of Conduct.
Ajay Dyavathi is a new contributor. Be nice, and check out our Code of Conduct.
Ajay Dyavathi is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Welcome to Mathematica SE. If you want good answers, please provide a minimal example of a differential equation so that people can demonstrate Mathematica's capabilities more concretely.
$endgroup$
– Roman
1 hour ago